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AysviL [449]
3 years ago
12

Identify the reference angle ∅ for each given angle, 0.

Mathematics
1 answer:
frutty [35]3 years ago
5 0

Answer:

When Ø = 300°, Ø = 60 degrees.

When Ø = 225°, Ø = 45 degrees.

When Ø = 480°, Ø = 60 degrees.

When Ø = -210°, Ø = 30 degrees.

Step-by-step explanation:

Reference angles are in Quadrant I (0° to 90°).

1. Find 300° (Quadrant IV) on the unit circle. Since it's in Quadrant IV, you use 360 - 300 = 60° to get your answer.

2. Find 225° (Quadrant III) on the unit circle. Since it's in Quadrant III, you use 225 - 180 = 45° to get your answer.

3. The angle 480° is not on the unit circle. To find its corresponding angle between 0° and 360°, use 480 - 360 = 120°. Then, find 120° (Quadrant II) on the unit circle. Since it's in Quadrant II, you use 180 - 120 = 60° to get your answer.

4. The angle -210° is not on the unit circle. To find its corresponding angle between 0° and 360°, use -210 + 360 = 150°. Then, find 150° (Quadrant II) on the unit circle. Since it's in Quadrant II, you use 180 - 150 = 30° to get your answer.

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The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

Step-by-step explanation:

Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88

At the null hypothesis, we test if the proportion is of 0.88, that is:

H_0: p = 0.88

At the alternate hypothesis, we test if this proportion is less than 0.88, that is:

H_a: p < 0.88

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.88 is tested at the null hypothesis:

This means that \mu = 0.88, \sigma = \sqrt{0.88*0.12}

A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.

This means that n = 160, X = \frac{138}{160} = 0.8625

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z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

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The p-value of the test is the probability of finding a sample proportion below 0.8625, which is the p-value of z = -0.68.

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The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

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