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1 year ago

Please help me! (this is from khan academy 6th grade math!)

Mathematics

1 answer:

Svetach [21]1 year ago

8 0

Answer:

1st → 1st

2nd → 3rd

3rd → 2nd

Step-by-step explanation:

just divide the first set of student wishes to the second set of students in the same question. the 1st for example

x-ray to all students is 6/ 36= 1/6 = 1:6

for all students, you add all the students in the table

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14(0.89)^x+4.5 =162

lisabon 2012 [21]

$14(0.89)^{x + 4.5} = 162$
$\frac{14(0.89)^{x + 4.5}}{14} = \frac{162}{14}$
$0.89^{x + 4.5} = 11\frac{4}{7}$
$ln(0.89^{x + 4.5}) = ln(11\frac{4}{7})$
$(x + 4.5)ln(0.89) = ln(11\frac{4}{7})$
$\frac{(x + 4.5)ln(0.89)}{ln(0.89)} = \frac{ln(11\frac{4}{7})}{ln(0.89)}$
$x + 4.5 = -2101.14032500$
$x = 2105.64032500$

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3 years ago

We are planning a reception for our daughter. The hall that we are renting charges a $90 cleanup fee. In addition to the cleanup

iris [78.8K]

Answer:

The equation is y = 29x + 90. So, if you plug in 3,100.00 for y.

3,100.00 = 29x + 90

3,100.00 - 90 = 29x

3,010.00 = 29x

3,010.00/29 = 29x/29

x = 103 guests

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3 years ago

What is the range of the data? 2,8,7,8,6,15,6,3,8

creativ13 [48]

Answer:

Step-by-step explanation:

The range of a data set is the difference between the greatest and least values in the set. In this case, the greatest value is 15 and the least value is 2 so the range is 15 - 2 = 13.

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3 years ago

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$