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Nana76 [90]
3 years ago
14

There 400 members at the school band. Of those, 220 were girls. Expressed as a percentage, how many more girls than boys were th

ere at school band? (PLEASE SHOW STEPS!)
Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
220/400 = 55%
100%- 55% = 45%
there were 45% more girls than there were boys.
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describe the effect of change on the area of the rectangle if the base and height are both multiplied by 1/2
VladimirAG [237]

Answer:

The area would decrease

Step-by-step explanation:

So if the base was 4ft and the height was 2ft then the area would be 8ft^2. because area is base times height. so if 4 times 1/2 is 2 and 2 time 1/2 is 1 so the area would be 2ft^2

7 0
3 years ago
A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500
Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking,\frac{d(w)}{dt} = 3 ft/sec

Rate at which the man is walking,\frac{d(m)}{dt} = 2 ft/sec

Collective rate of both, \frac{d(m+w)}{dt} = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min  = 20 min

Now,

Distance traveled by man and woman are m and w ft respectively.

⇒ m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft

⇒ w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\  ft

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate \frac{dh}{dt} .

Lets calculate h.

Applying Pythagoras formula.

⇒ h^2=(m+w)^2+500^2  

⇒ h=\sqrt{(2400+2700)^2+500^2} = 5124.45

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ h^2=(m+w)^2+500^2

⇒ 2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt}  + \frac{d(500)}{dt}

⇒ \frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}                         ...as \frac{d(500)}{dt}= 0

⇒ Plugging the values.

⇒ \frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}                       ...as \frac{d(m+w)}{dt} = 5 ft/sec

⇒ \frac{d(h)}{dt} =4.9761  ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0
3 years ago
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denis-greek [22]

Answer:

Step-by-step explanation:

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6 0
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OLga [1]

Answer: 42.9%

Step-by-step explanation:

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Step-by-step explanation:

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