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Ksju [112]
3 years ago
11

Miranda was babysittingfor a friends parents saturday morning and was paid $12.50 per hour. Later that evening, she was babysitt

ing for another couple that paid her $18.75 per hour for 5 hours. What was mirandas average rate of pay per hour for the day?
Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:

10-20 dollars per hour

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Shards of clay vessels were put together to reconstruct rim diameters of the original ceramic vessels found at the Wind Mountain
Otrada [13]

Answer:

a) In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)^2}{n-1}} (3)  

The mean calculated for this case is

The sample deviation calculated s=3.46 \approx 3.5

b) 15.8-1.383\frac{3.5}{\sqrt{10}}=14.27    

15.8+1.383\frac{3.5}{\sqrt{10}}=17.33    

So on this case the 80% confidence interval would be given by (14.27;17.33)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)^2}{n-1}} (3)  

The mean calculated for this case is

The sample deviation calculated s=3.46 \approx 3.5

Part b

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=10-1=9

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.1,9)".And we see that t_{\alpha/2}=1.383

Now we have everything in order to replace into formula (1):

15.8-1.383\frac{3.5}{\sqrt{10}}=14.27    

15.8+1.383\frac{3.5}{\sqrt{10}}=17.33    

So on this case the 80% confidence interval would be given by (14.27;17.33)    

6 0
3 years ago
How much elastic energy is stored in a slingshot that has a spring constant of 300 N/m and is stretched by 0.45m?
vagabundo [1.1K]

Answer:

E = 30.37 J

Step-by-step explanation:

Given that,

The spring constant of the spring, k = 300 N/m

The spring is stretched by 0.45 m, x = 0.45 m

We need to find the elastic energy stored in the spring. The formula for the elastic energy is given by :

E=\dfrac{1}{2}kx^2\\\\=\dfrac{1}{2}\times 300\times (0.45)^2\\\\=30.37\ J

So, the required elastic energy is equal to 30.37 J.

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Answer:

zebra

Step-by-step explanation:

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The answers D: Translated up 3 unit(s) and translated to the right 1 unit(s)

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9 + b is an expression

Step-by-step explanation:

Expressions don't have the = sign in them but equations do.

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