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Virty [35]
3 years ago
6

Can anyone help me with this question

Mathematics
2 answers:
madam [21]3 years ago
7 0

Answer:

The answer to this question is 9

borishaifa [10]3 years ago
4 0

ANSWER

9

EXPLANATION

The given radical is

\sqrt[3]{729}

We can rewrite this as

{(729)}^{ \frac{1}{3} }

Now we need to rewrite 729 as a power with an exponent of 3.

{(9 \times 9 \times 9)}^{ \frac{1}{3} }

{( {9}^{3} )}^{ \frac{1}{3} }  = {(9)}^{3 \times  \frac{1}{3} }  =  {9}^{1}  = 9

The third choice is correct.

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What is10 + 9 <br><br> i really dont know <br><br> can someone help me
Tresset [83]

\huge \green{ \boxed{ANSWER}}

10  \:  +  \: 9 \:  =  {\boxed{19}}

USE CALCULATOR -_-

\mathfrak{JazmineChoi}

<em><u>STAN </u></em><em><u>TREASURE</u></em>

8 0
2 years ago
Read 2 more answers
Math help me))))))))please
olasank [31]
X^2/(x- 9 = 81/(x - 9)
This is the equation for which you want the solution.
Multiplying both sides of the equation by (x - 9) we get
x^2(x - 9)/(x - 9) = 81(x - 9)/(x - 9)
So the (x - 9) goes out from both the denominator and the numerator and then the simplified equation becomes
x^2 = 81
x ^2 = (9)^2
x = 9
So the value of the unknown variable x comes out to be 9.
6 0
3 years ago
Read 2 more answers
Mark u as branliest but answer right plz
yanalaym [24]

Answer:

Step-by-step explanation:

55+4x

8 0
3 years ago
Water is leaking out of an inverted conical tank at a rate of 12,000 cm3/min at the same time that water is being pumped into th
Bas_tet [7]

Answer:

291111.1cm^3/min

Step-by-step explanation:

We are given that

\frac{dV}{dt}_{out}=12000 cm^3/min

Height of tank,h=6 m

Diameter of top,d=4 m

Radius,r=\frac{d}{2}=\frac{4}{2}=2 m

\frac{dh}{dt}=20 cm/min

\frac{r}{h}=\frac{2}{6}=\frac{1}{3}

r=\frac{1}{3} h

We have to find rate at which water is being pumped into the tank.

Volume of conical ,V=\frac{1}{3}\pi r^2 h

V=\frac{1}{3}\pi(\frac{1}{3} h)^2h=\frac{1}{27}\pi h^3

\frac{dV}{dt}=\frac{1}{9}\pi h^2(\frac{dh}{dt})

h=2 m=200 cm

1m=100 cm

\frac{dV}{dt}_{in}-12000=\frac{1}{9}\pi(200)^2\times 20

\frac{dV}{dt}_{in}=12000+\frac{1}{9}\pi (40000)\times 20

\frac{dV}{dt}_{in}=291111.1cm^3/min

4 0
3 years ago
Three cars are driving on a racetrack. The mean speed of the three cars is 100 miles per hour. Car X drives 109 miles per hour a
siniylev [52]

Answer:

B

Step-by-step explanation:

The mean is the average found by adding the sum of the data points and dividing by the number of them. Here there are 3 cars whose speeds are 109, 111, and Z or unknown. The mean of them is 100. Solve for Z.

100 =(109+111+Z)/3

300=220+Z

80=Z

The speed of Car Z is less than 100.

3 0
3 years ago
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