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3 years ago

how many quarter pound burgers can george make out of 3 1/2 pounds of ground beef? explanation please!

Mathematics

2 answers:

KengaRu [80]3 years ago

6 0

Answer:

We know that:

1 quarter pound = 0.25 of a pound.

Give that:

Total amount of ground beef = $3\frac{1}{2} = 3.5$ pound

From 3.5 pound of beef we have to make burgers using 0.25 pound of beef in one burger

We have to find how many burgers can be made:

We have to divide 3.5 pound by 0.25 pound

i.e,

$\frac{3.5}{0.25} = 14$

⇒14 quarter pounds burger can be made.

Therefore, 14 quarter pound burgers can George make out of 3 1/2 pounds of ground beef

Molodets [167]3 years ago

3 0

Think of the question as money. You have 3 dollars and 50 and you want to count by a quarter of much which is 25. Now you find the answer

You might be interested in

A rectangular field is 24 yards in length and 81 feet in width.

kondaur [170]

Ok,
First, you have to make the measurements in feet. 24 yards = 72 feet
Then do 72 x 81 = 5832 square feet

Then,
First, you have to make the measurements in yards. 81 feet = 27 yards
Then do 24 x 27 = 648 square yards

Hope this helps :D

4 0

3 years ago

A stop sign is a regular octagon. The standard stop sign has a 16.2 inch radius. The area of a standard stop sign is ___________

juin [17]

The area of standard stop sign regular octagon is 742.3 squared inches, if the standard stop sign has a 16.2 inch radius.

Step-by-step explanation:

The given is,

Radius of standard stop sign is 16.2 inch radius

Step:1

The regular octagon is equal to the 16 right angled triangle,

Angle of right angle triangle = $\frac{360}{16}$ = 22.5°

Ref attachment,

From the OAB right angle triangle,

Trigonometric ratio,

sin ∅ = $\frac{Opp}{Hyp}$

Where, ∅ = 22.5°

Hyp = Radius = 16.2 inches

Ratio becomes,

sin 22.5°= $\frac{b}{16.2}$

b = (0.374607)(16.2)

b = 6.19947 inches

Trigonometric ratio,

cos ∅ = $\frac{Adj}{Hyp}$

Where, ∅ = 22.5°

Hyp = Radius = 16.2 inches

Adj = h

Ratio becomes,

cos 22.5°= $\frac{h}{16.2}$

h = (0.9238795)(16.2)

h = 14.967 inches

Step:2

From the triangle OAC,

Area, $A = \frac{1}{2} (Height )( Base)$

Where, Height = 14.967 inches

Base = b + x = 6.19947 + 6.19947

= 12.3989 inches

From the values equation becomes,

A = $\frac{1}{2} (14.967)(12.39894)$

A = 92.7875 Squared inches

Step:3

The octagon is equal to sum of 8 triangles

Area of octagon = 8 × Area of triangle

= 8 × 92.7875

= 742.3 squared inches

Result:

The area of standard stop sign regular octagon is 742.3 squared inches, if the standard stop sign has a 16.2 inch radius.

7 0

3 years ago

I need help fast !!

AysviL [449]

<h2>Answer:</h2>

Luke does a work of 308Nm

<h2>Step-by-step explanation:</h2>

If we have a constant force $\vec{F}$ that acts on a body in the same direction as the displacement $\vec{s}$ , then the work $W$ is defined as the product of the force magnitude $F$ and the displacement magnitude $s$ . In other words: