Question

The environmental protection agency is attempting to revive 3 acres of contaminated soil by replacing the top 24 inches of the soil.trucks with a hauling capacity of 28 cubic yards of soil are hired to remove the contaminated soil. how many full truckloads of contaminated soil will be hauled away?​

Answer 1

Answer:

$346\ trucks$

Step-by-step explanation:

1 acre equals to 4840 yard²

So

$3\ acres *\frac{4840\ yard^2}{1\ acre}= 14520\ yard^2$

Also

$1\ in = 0.02778\ yard$

So

$24\ in *\frac{0.02778\ yard}{1\ in}= 0.667\ yard$

So volume V of the contaminated area is:

$V = 14520*0.667\ yard^3\\\\V=9680.48\ yard^3$

If each truck has a capacity of 28 cubic yards then it is necessary

$9680.48\ yard^3 * \frac{1\ truck}{28\ yard^3}=346\ trucks$