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Jet001 [13]
3 years ago
8

The environmental protection agency is attempting to revive 3 acres of contaminated soil by replacing the top 24 inches of the s

oil.trucks with a hauling capacity of 28 cubic yards of soil are hired to remove the contaminated soil. how many full truckloads of contaminated soil will be hauled away?​
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
5 0

Answer:

346\ trucks

Step-by-step explanation:

1 acre equals to 4840 yard²

So

3\ acres *\frac{4840\ yard^2}{1\ acre}= 14520\ yard^2

Also

1\ in = 0.02778\ yard

So

24\ in *\frac{0.02778\ yard}{1\ in}= 0.667\ yard

So volume V of the contaminated area is:

V = 14520*0.667\ yard^3\\\\V=9680.48\ yard^3

If each truck has a capacity of 28 cubic yards then it is necessary

9680.48\ yard^3 * \frac{1\ truck}{28\ yard^3}=346\ trucks

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Answer:   A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

<u>Step-by-step explanation:</u>

                  \left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right]

Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right]

Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

5 0
3 years ago
What sum of money amounts to rupees 545 4 at 8% BA in 30 months​
Mars2501 [29]

Answer:

let sum of money be x

amount=rupees5454

rate=8%

time=30 months

convert month into year

30/12=5/2 years

Step-by-step explanation:

interest=p*t*r/100

=x*5*8/100*2

=40x/200

=x/5

so to find principal use formula

amount=principal +interest

5454=x+x/5

5454=5x+x/5

5454*5=6x

27270/6=x

4545=x

therefore ,sum of money(principal)=rupees.4545

Hope this helps u!!

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