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3 years ago

Explain the relationship between tangent and the slope of a line

2 answers:

7 0

<span>The secant line is a line that connects two points on the graph of a function. The tangent line is the line that is basically the slope of a function at a given point. (So secant line is the slope of a line through TWO points, tangent line is slope of a function at ONE point) The derivative finds the slop at any given point on a function. Basically the derivative is the tangent line at ANY point given for the function f(x).
</span>

pashok25 [27]3 years ago

6 0

<span>The secant line is a line that connects two points on the graph of a function. The tangent line is the line that is basically the slope of a function at a given point</span>

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4 and 9/10 minus 2 and 2/5 = (in fractions)

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Answer:

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Step-by-step explanation:

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3 years ago

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How to find out how many cubes it takes? Can someone explain to me how to do the how many cubes does it take thing?

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In this case, you simply count how many cubes are in the length, width, and height and multiply them together. In the example problem, the answer is 75 blocks because the dimensions are 5 x 5 x 3.

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3 years ago

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4 years ago

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abruzzese [7]

Answer:SAS

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3 years ago

There are currently 16 teams in the National Football Conference (NFC). Of those teams, 11 have won at least one super bowl and

svp [43]

You are given 16 teams, 11 have won at least one super bowl and 5 have not.

A. The probability that both selected teams have won at least 1 super bowl is

$Pr(A)=\dfrac{C_{11}^2}{C_{16}^2}=\dfrac{\dfrac{11!}{2!(11-2)!}}{\dfrac{16!}{2!(16-2)!}}=\dfrac{\dfrac{10\cdot 11}{2}}{\dfrac{15\cdot 16}{2}}=\dfrac{55}{120}=\dfrac{11}{24}.$

B. The probability that neither selected team has won at least 1 super bowl is

$Pr(B)=\dfrac{C_{5}^2}{C_{16}^2}=\dfrac{\dfrac{5!}{2!(5-2)!}}{\dfrac{16!}{2!(16-2)!}}=\dfrac{\dfrac{4\cdot 5}{2}}{\dfrac{15\cdot 16}{2}}=\dfrac{10}{120}=\dfrac{1}{12}.$

C. The probability that at least one selected team has won at least 1 super bowl is

$Pr(C)=1-Pr(B)=1-\dfrac{1}{12}=\dfrac{11}{12}.$

D. to find the probability that the second team selected has won at least 1 super bowl given that the first team selected has not won a super bowl, consider such events:

P - the second team selected has won at least 1 super bowl;

Q - the first team selected has not won a super bowl.

Then

$Pr(P|Q)=\dfrac{Pr(P\cap Q)}{Pr(Q)}=\dfrac{\dfrac{5\cdot 11}{C_{16}^2}}{\dfrac{C_5^1\cdot C_{15}^1}{C_{16}^2}}=\dfrac{55}{75}=\dfrac{11}{15}.$

E. To find the probability that the second team selected has won at least 1 super bowl given that the first team selected has won at least 1 super bowl, consider events:

M - the second team selected has won at least 1 super bowl;

N - the first team selected has won at least 1 super bowl.

Then

$Pr(M|N)=\dfrac{Pr(M\cap N)}{Pr(N)}=\dfrac{\dfrac{11\cdot 10}{C_{16}^2}}{\dfrac{C_{11}^1\cdot C_{15}^1}{C_{16}^2}}=\dfrac{110}{165}=\dfrac{2}{3}.$

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3 years ago