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3 years ago

15

Math question down below

2 answers:

ioda3 years ago

4 0

110. It's the farthest away from them all.

brilliants [131]3 years ago

4 0

The correct answer is 12

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10PTS: Prove/show that the limit of a constant as x approaches infinity is that constant?

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If the values of a function f(x) approach the value L as x approaches c, we say that f(x) has the limit L as x approaches c, and we write

In simpler terms, as x approaches c, the value of f(x) approaches L.

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3 years ago

If I have a 94 in my class and my final exam is worth 10%, what would be my final score if I make a 50? (I'm setting the bar low

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3 years ago

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Please help me with this probability question, I’ve got my maths exam tomorrow (13th June)

Evgen [1.6K]

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2 years ago

What is the volume of a cylinder with a height of 12.8 m and a base with a radius of 5.7 m, to the nearest tenth of a cubic mete

saul85 [17]

Answer: 1306.5 m^3

Step-by-step explanation:

1. The formula for the volume of a cylinder is: V= $\pi$ r^2h

2. If you substitute the values into the equation, you get

V = pi * 5.7^2 * 12.8 = 1306.5

3. 1306.5 is already to the nearest tenth, so that is the answer.

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3 years ago

Use the position function s(t) = –4.9t2 + 500, which gives the height (in meters) of an object that has fallen for t seconds fro

weqwewe [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is $v(3) = 29.4 \ m/s$

Step-by-step explanation:

From the question we are told that

$s(t) = -4.9t^2 + 500$

And

$\lim_{t \to a} \frac{s(a) - s(t)}{a-t}$

Generally s(t) at t = a is mathematically evaluated as

$s(a) = -4.9a^2+ 500$

So

$s(a) - s(t) = -4.9a^2 + 500 - ( -4.9t^2+500)$

$s(a) - s(t) = -4.9a^2 + 500 +4.9t^2-500)$

$s(a) - s(t) = 4.9(t^2 - a^2)$

Thus the velocity is represented as

$v(t) =\lim_{t \to a} \frac{s(a) - s(t)}{a-t} \equiv \lim_{t \to a} \frac{4.9(t^2 - a^2 )}{ a-t}$

=> $v(t) = \lim_{t \to a} - 4.9(a + t )$

=> $v(t) = -4.9 (a + a )$

=> $v(t) = -9.8a$

Now at t = 3

=> $v(3) = -9.8 (3)$

=> $v(3) = 29.4 \ m/s$

3 0

4 years ago