Question

The ice at a certain hockey rink is made by freezing water that is 1.5 inch deep. how many gallons of water does it take? approximate the rink as a 200 ft by 85 ft rectangle

Answer 1

The rink has a dimension of 200 ft* 85 ft = 17000 $ft^{2}$

depth = 1.5 inch that becomes $\frac{1.5}{12}$ = 0.125 ft

So total volume of the water required = 17000* 0.125 = 2125 $ft^3$

Now 1 cubic foot of water= 7.480 gallons

Hence total gallons required are 2125 * 7.480 gallons = 15895 gallons.