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lorasvet [3.4K]
2 years ago
14

Help please i don’t understand

Mathematics
1 answer:
My name is Ann [436]2 years ago
3 0

Answer:

B or C

Step-by-step explanation:

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On the Venn diagram, which region(s) represent the union of Set A and Set B (A⋃B)?
slega [8]
The set A U B is represented by shading both circles A and B (also the overlapping region as well). Any point in set A U B will be in either A, B or both. 
7 0
3 years ago
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8. You recorded the time in seconds it took for 8 participants to solve a puzzle. The times were: 15.2, 18.8, 19.3, 19.7, 20.2,
kirill115 [55]

Answer:

Xbar = 20.813

Median = 19.95

5 - number summary :

Minimum = 15.2

Q1 = 19.05; Q2 = 19.95 ; Q3 = 21.95 ; maximum = 29.4

Standard deviation, s = 4.068

Step-by-step explanation:

Given the data:

X : 15.2, 18.8, 19.3, 19.7, 20.2, 21.8, 22.1, 29.4

Ordered data:

15.2, 18.8, 19.3, 19.7, 20.2, 21.8, 22.1, 29.4

The mean (xbar) :

Xbar = Σx / n ; n = sample size = 8

Xbar = 166.8 / 8 = 20.8125

Xbar = 20.813

The median :

1/2 *(n+1)th term

1/2(9) = 4.5

(4 + 5)th term / 2

(19.7 + 20.2) / 2 = 19.95

The five number summary :

Minimum = 15.2

Lower quartile (Q1) = 1/4(9) = 2.25 ; (2nd + 3rd) term / 2

(18.8 + 19.3) / 2 = 19.05

Median (Q2) = 19.95

Upper quartile (Q3) :

3/4(9) = 6.75 = (6th + 7th) / 2

(21.8 + 22.1) / 2 = 21.95

Maximum = 29.4

The standard deviation, s = sqrt[(x - xbar)²/ (n-1)]

Using calculator ;

s = 4.068

4 0
2 years ago
The sum of 55+66 as the product of their gcf and another sum
marusya05 [52]
55+66=121 \\\\ 55|5 \\11|11 \\1 \\\\ 55=5*11 \\\\ 66|6\\11|11\\1 \\\\66=6*11 \\\\ G.C.F(55;66)=11 \\\\ 11*x=121 \\\\ x=3+8 \\\\ \boxed{11*(3+8)=121}
3 0
3 years ago
Read 2 more answers
A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer
OLEGan [10]

Answer:

The probability is  P( p <  0.9207) = 0.0012556

Step-by-step explanation:

From the question we are told

  The population proportion is p = 0.96

 The sample size is  n  =  227

 The number of graduate who had job is  k = 209

Generally given that the sample size is large enough  (i.e n >  30) then the mean of this sampling distribution is  

       \mu_x = p = 0.96

Generally the standard deviation of this sampling distribution is  

    \sigma  = \sqrt{\frac{p (1 - p )}{n} }

=>  \sigma  = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }

=>  \sigma  = 0.0130

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{k}{n}

=> \^ p =  \frac{209}{227}

=> \^ p =  0.9207

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

     P( p <  0.9207) = P( \frac{\^ p - p }{\sigma } <  \frac{0.9207 - 0.96}{0.0130 }  )

\frac{\^ p - p}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \^ p )

   P( p <  0.9207) = P(Z< -3.022 )

From the z table  the area under the normal curve to the left corresponding to    -3.022  is

     P(Z< -3.022 ) = 0.0012556

=> P( p <  0.9207) = 0.0012556

6 0
3 years ago
Please help, I rally need ir
Mnenie [13.5K]

Answer:

The one on the top at you’re right

3 0
2 years ago
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