Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
8/25 is the simplest form
Answer:
Step-by-step explanation:
1.Based on the equation the y-intercept is -2(go down 2 places on the y axis)
2.Since here is only x in the equation the rise over run will be 1/-1 (go up 1 and to the left 1 from the point -2 on the y axis) keep doing that all the way down the graph marking your points, also reverse the process going down 1 and to the right 1 to mark the points on the opposite side.
3.Draw the line through the points you marked from step 2
4.In the equation it is x-2 so it is a positive slope and a negative y-intercept
m=1
b= -2
Answer:
its D Q and O
Step-by-step explanation:
Answer:
-5y + 6 = -9
y = 3
Step-by-step explanation:
subtract 6 from both sides
-5y + 6 - 6 = -9 - 6
simplify
-5y = -15
divide both sides by -5
(-5y)/5 = (-15)/5
simplify
y = 3
