1) Formula: area = height * base / 2
2) Call x the height:
height = x
base = 2x
3) State the equation:
(x)(2x) = 49 in^2
4) Solve the equation:
2x^2 = 49 in^s
x^2 = (49/2) in^2
x = √(49/2) in
x = 7√2 / 2 in = 3.5 √2 in
5) Solution:
height = 3.5 √2 in and base = 7√2 in
6) Verification: area = (7√2 in) (3.5√2 in) = 49 in^2
Answer: height = 3.5√2 in and base = 7√2 in.
Answer: D) 13y^25 and 2y^25
Like terms involve the same variables, and each of those variables must have the same exponents.
Another example of a pair of like terms would be 5x^3y^2 and 7x^3y^2. Both involve the variable portion "x^3y^2" which we can replace with another variable, say the variable z. That means 5x^3y^2 becomes 5z and 7x^3y^2 becomes 7z. After getting to 5z and 7z, it becomes more clear we have like terms.
5500 is the awnser I came up with
Answer:
y=4
Step-by-step explanation:
You can ignore the 3 and 6 because this has no y value change(rise over run)
This is a straight horizontal line so the equation is y=4.
Slope=0
Answer:
19 people
Step-by-step explanation:
To find how many people went to the mall, count each x
At 0 trips, there are 2 xs, so<u> 2</u> people had 0 trips to the mall
At 1 trip, there are 0 xs, so <u>0</u> people had 1 trip to the mall
At 2 trips, there are 10 xs, so <u>10 </u>people had 2 trips to the mall
At 3 trips, there are 7 xs, so <u>7</u> people had 3 trips to the mall
Add up all the xs
2+0+10+7=19
19 people in all
