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emmainna [20.7K]
3 years ago
9

What is the ratio of 24 to 32

Mathematics
2 answers:
max2010maxim [7]3 years ago
8 0
24*x=32
x=32/24=4/3
Hope this helps
lubasha [3.4K]3 years ago
6 0
It is 3 to 4
you find the GCF of 24 and 32 which is 8. then divide 24 and 32 by 8 to find the ratio
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A dog breeder plans to mix two types of food to make a mix of low cost
lys-0071 [83]

Answer:

  • 3.75 bags of ChowChow
  • 0.75 bags of Kibble

Step-by-step explanation:

The constraints on protein, minerals, and vitamins give rise to the inequalities ...

  40c +30k ≥ 150 . . . . . . required protein

  20c +20k ≥ 90 . . . . . . required minerals

  10c +30k ≥ 60 . . . . . . . required vitamins

And we want to minimize 10c +12k.

The graph shows the vertices of the feasible region in (c, k) coordinates. The one that minimizes cost is (c, k) = (3.75, 0.75).

To minimize cost, the daily feed should be ...

  • 3.75 bags of ChowChow
  • 0.75 bags of Kibble

Daily cost will be $46.50.

5 0
3 years ago
Without calculating the answer for 5 1/5 * 2/5 be larger or smaller than 5 1/5​
solniwko [45]

Answer:

Evidently, without the calculating 5 1/5 times 2/5 would be larger than 5 1/5 since you are already gonna multiply 2/5 and that would make it larger.

Hope this helps!

Branliest would be appreciated :DD

Step-by-step explanation:

4 0
3 years ago
PLZ HELP ME! Whoever gets it right will be marked brainiest
Brut [27]

Answer:

Probability that Hannah only has to buy 3 or less boxes before getting a prize is 0.784

Step-by-step explanation:

Given, 40% of cereal boxes contain a prize

⇒probability of getting a prize on opening a box, P(A)=0.4

where A is the event of getting a prize on opening a cereal box

and probability of not getting a prize on opening a box, P(A')=1-P(A)=0.6

where A' is the event of not getting a prize on opening a cereal box

This problem needs to be divided into 3 situation:

  • Case 1, Where Hannah gets prize when she buys the first box:

Let K be the event of Hannah winning the prize on buying the first box.

⇒P(K)=P(A)=0.4

  • Case 2, Where Hannah gets prize when she buys the second box:

I<u>n this event Hannah should not get the prize in first box but should get the prize on buying the second box</u>

Let L be the event of Hannah winning the prize on buying the second box

So, P(L)=P(A')·P(A)

           =(0.6)·(0.4)

           =0.24

  • Case 3,Where Hannah gets prize when she buys the third box:

<u>In this event Hannah should not get the prize in first and second box but should get the prize on buying the third box</u>

Let L be the event of Hannah winning the prize on buying the third box

So, P(L)=P(A')·P(A')·P(A)

           =(0.6)·(0.6)·(0.4)

           =0.144

Let N be the event of Hannah winning the prize on buying 3 or less boxes before getting a prize

⇒N=K∪L∪M

Now, Required probability is P(N)=P(K∪L∪M)=P(K)+P(L)+P(M) [As events K,L and M are independent and disjoint events]

⇒P(N)=0.4+0.24+0.144

         =0.784

7 0
3 years ago
What are the vertical and horizontal asymptotes for the function f(x)=3^2/x^-4
Zarrin [17]

The vertical asymptotes x = - 2, 2 and Horizontal asymptotes y = 3

Option A is the correct answer.

<h3>What are Function?</h3>

Function are mathematical statement which links an independent variable to dependent variable.

It always comes with a defined domain and range.

The equation mentioned is incorrect in the question w.r.t. to the solutions mentioned, The right equation is

\rm f(x) = \dfrac{3 x^2}{x^{2}-4}

This function can also be written as

\rm f(x) = \dfrac{3 x^2}{x^{2}-2^2}\\\\\rm f(x) = \dfrac{3 x^2}{(x+2)(x-2)}

Vertical asymptotes are defined when the denominator of a rational function tends to zero.

To find the equation/s let the denominator equal zero.

Denominator tends to zero for x = -2 and x = +2

Horizontal Asymptote is when the function f(x) is tending to zero.

for x = +∞ and x = - ∞

Let the rational function f(x)= \dfrac{mx^a}{nx^b}  where  and a and b are degree of numerator and denominator.

If a < b , then the y axis y = 0 is a horizontal asymptote.

If b = a then horizontal asymptote is the line y = p/q

Here the value is b = 2 and a = 2

Since b = a the horizontal asymptote is the line

y = m/n  where m = 3 and n = 1

Therefore y = 3

So , vertical asymptotes x = - 2, 2

Horizontal asymptotes y = 3

Option A is the correct answer.

To know more about Function

brainly.com/question/12431044

#SPJ1

8 0
2 years ago
1.6.15
pishuonlain [190]
The maximum messages are 224
3 0
3 years ago
Read 2 more answers
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