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krek1111 [17]
3 years ago
8

HELP ASAPPPPPP! I HAVE BEEN WAITING FOR 20 MIN PLS HELP ME! A prism and two nets are shown below: Image of a right triangular pr

ism and 2 nets. The triangle bases have base 4, height 3, and diagonal side 5. The length of the prism from the bases is 8.6. Net A has 3 rectangles in a row. The middle one has sides AC and CD. This middle one has triangle ABC on top and identical triangle below. Net B is the same except that the triangle base ABC is on top of the last rectangle which has sides AC and CD. Units are in inches. Part A: Which is the correct net for the prism? Explain your answer. (2 points) Part B: Write the measurements of Sides AB, BC, and CD of the correct net. (4 points) Part C: What is the surface area of the prism? Show your work. (4 points)

Mathematics
1 answer:
olga_2 [115]3 years ago
6 0

Answer:

brainly.com/question/17042305?answeringSource=feedPersonal%2FquestionPage%2F1

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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20 less than 12 times a number is 64. what is the number
igomit [66]
X = 12y - 20

y = 12y

Y is obviously greater than 20 when you multiply it by 12, so that's a hint.

x = 42

y = 22

3.5 • 12 + 22 = 64

I hope this helped you!

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3 years ago
A lumber company is making doors that are 2058.02058.0 millimeters tall. If the doors are too long they must be trimmed, and if
nataly862011 [7]

Answer:

t=\frac{2044-2058}{\frac{17}{\sqrt{15}}}=-3.190    

df=n-1=15-1=14  

p_v =P(t_{(14)}    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly lower than 2058 mm at 5% of signficance.  

Step-by-step explanation:

Data given and notation    

\bar X=2044 represent the sample mean    

s=17 represent the sample standard deviation    

n=15 sample size    

\mu_o =2058 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is lower than 2058 mm, the system of hypothesis are :    

Null hypothesis:\mu \geq 2058    

Alternative hypothesis:\mu < 2058    

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{2044-2058}{\frac{17}{\sqrt{15}}}=-3.190    

P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=15-1=14  

Since is a one-sided lower test the p value would be:    

p_v =P(t_{(14)}    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly lower than 2058 mm at 5% of signficance.  

8 0
3 years ago
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