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photoshop1234 [79]
2 years ago
6

The first S-number is 1. The second S-number is the sum of the first S-number and the second odd number. The third S-number is t

he sum of the second S-number and the third odd number. The fourth S-number is the sum of the third S-number and the fourth odd number, etc., …… Compute the first seven S-numbers. Make a note of any patterns you notice. Enter the first seven S-numbers as a comma-separated list:
Mathematics
1 answer:
vitfil [10]2 years ago
5 0

Answer:

  • Sn = n^2 . . . . . . the pattern
  • {1, 4, 9, 16, 25, 36, 49}

Step-by-step explanation:

The consecutive differences between S-numbers are (by definition) consecutive odd numbers. This by itself indicates that S-numbers are defined by a quadratic formula. As it happens, ...

  Sn = n^2

___

  S1 = 1 . . . . given

  S2 = S1 + 3 = 4

  S3 = S2 + 5 = 9

  S4 = S3 + 7 = 16

  S5 = S4 + 9 = 25

  S6 = S5 +11 = 36

  S7 = S6 +13 = 49

A list of the first 7 S-numbers is ...

  {1, 4, 9, 16, 25, 36, 49}

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Eric orders 3 large cheese pizzas. There is a $2 delivery fee for each pizza.He pays a total of $42.Which equation can be used t
ad-work [718]

Answer:

3(x+2)=42

Step-by-step explanation:

So lets go over what we know:

There are 3 large pizzas

Each pizza has a addition cost of 2 dollars

The total cost is 42 dollars

We need to find the cost per pizza.

Now lets piece together our equation.

We know that the pizzas equal 42 dollars so we can immediately put 42 on the opposite side of the equal side:

=42

We also know that each of the 3 pizzas cost 2 dollars. This would go on the left side of the equation:

6=42
Now, we know x is the amount of pizzas. There are 3 pizzas, or in other words, 3x. We can add this to the left side of the equation, because the 3 pizzas plus the 6 dollars equals the total of 42 dollars:

3x+6=42

There are no answers above that look like this, however. This is because we have to factor the left side of the equation.

A factor of both 3 and 6 is 3. So we can factor out 3 and we get:

3(x+2)=42

This looks like the first answer!
Hope this helps! :3

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2 years ago
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slavikrds [6]
I don’t really see the question ?
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600/480 as a fraction in m/n form
Julli [10]

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Step-by-step explanation:

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2 years ago
How many different 10 person committees can be selected from a pool of 23 people?
Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

C(n,r)=\dfrac{n!}{(n-r)!r!}

Where n represents the number of objects/people in the set and r represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

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Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

=1,144,066

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
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stich3 [128]
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I hope this helped, and have a nice day!

4 0
2 years ago
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