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marusya05 [52]
2 years ago
7

Occlusion of the left anterior descending artery during a myocardial infarction would interrupt blood supply to which structures

?
Biology
1 answer:
Westkost [7]2 years ago
8 0
I believe it would interrupt blood supply to the left and right ventricles and much of the interventricular septum. Myocardial infarction (heart attack) occurs when blood flow decreases or  fails to reach parts of the heart, causing damage to the heart muscle. Occlusion of the left anterior descending artery may cause infarction of the anterior wall of the left ventricle, manifested as precordial ST-segment elevations. 
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Investiga como se reproducen las células madres​
Damm [24]

Answer:

Las células madre son células que se reproducen constantemente y tienen la capacidad de transformarse en cualquier otro tipo de célula del cuerpo de un organismo. Una célula a partir de la cual pueden crecer todos los tejidos del cuerpo, o una gran parte de ellos, es obviamente una célula extremadamente útil.  

Si las células madre se guían en la formación de tejidos sanos y funcionales, entonces, potencialmente, la terapia celular podría aplicarse para muchas enfermedades. De hecho, si las células provienen del propio paciente, en teoría no habrá riesgo de su rechazo (como lamentablemente ocurre con los trasplantes).

Las células madre tienen la capacidad de reproducirse por sí mismas a través del proceso de mitosis celular, para crear copias idénticas (clones) de sí mismas..

8 0
2 years ago
in 1952 franklin rosalind took a x-ray photograph shown below, which gave the world its first glance at DNA. In studying this ph
nasty-shy [4]
The structure of dna
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2 years ago
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is
IgorC [24]

Answer:

When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0

Explanation:

According to Levin's model (1969):

<em>dP/dt = c - e</em>

where P represents the proportion of occupied patches.

<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.

Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:

  • if dP/dt >0, then P is increasing with time
  • if dP/dt <0, then P is decreasing with time
  • if dP/dt = 0, then P is remaining the same with time.

The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).

c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0  and  1.

As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.

7 0
3 years ago
This illustration shows a kind of animal that is a parasitic organism. What is the common name of this organism?
zhannawk [14.2K]
EW i believe its A though
7 0
3 years ago
Read 2 more answers
What is the probability of getting offspring that are heterozygous for smooth AND heterozygous for yellow from a cross between p
meriva

Answer:

The probability of getting offspring that are heterozygous for smooth AND heterozygous for yellow, RrYy is 1/4 = 25%.

Explanation:

Due to technical problems, you will find the complete explanation in the attached files.

Download pdf
4 0
3 years ago
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