The equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3
The line is passing through the point = (-6,-3)
The slope of the line = 0
The point slope form is
Substitute the values in the equation
(y-(-3)) = 0×(x-(-6))
We have to convert this equation the slope intercept form
Slope intercept form is
y = mx + b
Where m is the slope of the line
b is the y intercept
(y-(-3)) = 0×(x-(-6))
y+3 = 0×(x+6)
y+3 = 0
y = -3
Hence, the equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3.
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Answer:
B) 81π units²
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Geometry</u>
Radius of a Circle Formula: r = d/2
Area of a Circle Formula: A = πr²
Step-by-step explanation:
<u>Step 1: Define</u>
Diameter <em>d</em> = 18 units
<u>Step 2: Manipulate Variables</u>
Radius <em>r</em> = 18 units/2 = 9 units
<u>Step 3: Find Area</u>
- Substitute in <em>r</em> [Area of a Circle Formula]: A = π(9 units)²
- [Area] Evaluate exponents: A = π(81 units²)
- [Area] Multiply: A = 81π units²
Answer:
a. 6
b. 9
Step-by-step explanation:
a. The product modulo 7 can be found from the product of the individual numbers modulo 7:
(88·95·36·702) mod 7 = (88 mod 7)·(95 mod 7)·(36 mod 7)·(703 mod 7) mod 7
= (4·4·1·3) mod 7 = 48 mod 7 = 6
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b. Powers of 4 mod 11 repeat with period 5:
4 mod 11 = 4
4^2 mod 11 = 5
4^3 mod 11 = 9
4^4 mod 11 = 3
4^5 mod 11 = 1
So, 4^83 mod 11 = 4^3 mod 11 = 9
Answer:
No, because an expression is already solved and an equation is where you have to solve it
Step-by-step explanation:
