Answer:
slope 2.500
x intercept 1.80000
m intercept 4.50000
Step-by-step explanation:
<u>step 1:</u>
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
5*(x+4)-(-2*(-4-m)+3)=0
<u>step</u><u> </u><u>2</u><u>:</u>
-4 - m = -1 • (m + 4)
(5•(x+4))-((0--2•(m+4))+3) = 0
<em>step</em><em> </em><em>3</em><em>:</em>
5 • (x + 4) - (2m + 11) = 0
<u>step</u><u> </u><u>4</u><u>:</u>
5x - 2m + 9 = 0
<u>step</u><u> </u><u>5</u><u>:</u>
Solve 5x-2m+9 = 0
B I’m guessing, never really worked with something like this before though
Answer:
the slope is 2
Step-by-step explanation:
Answer:
1,809.98 lb*m/s^2
Step-by-step explanation:
First, we want to know how much weight of the boulder is projected along the path in which the boulder can move.
The weight of the boulder is:
W = 322lb*9.8 m/s^2 = (3,155.6 lb*m/s^2)
This weight has a direction that is vertical, pointing downwards.
Now, we know that the angle of the hill is 35°
The angle that makes the direction of the weight and this angle, is:
(90° - 35°)
(A rough sketch of this situation can be seen in the image below)
Then we need to project the weight over this direction, and that will be given by:
P = W*cos(90° - 35°) = (3,155.6 lb*m/s^2)*cos(55°) = 1,809.98 lb*m/s^2
This is the force that Samuel needs to exert on the boulder if he wants the boulder to not roll down.