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ivolga24 [154]
3 years ago
8

Tranquilizing drugs that inhibit sympathetic nervous system activity often effectively reduce people's subjective experience of

intense anger or anxiety. Use one of the major theories of emotion to account for the emotion-reducing effects of such tranquilizers. Which theory of emotion would have the greatest difficulty explaining these effects? Why?
Engineering
1 answer:
bagirrra123 [75]3 years ago
6 0

Answer: There are different types of emotion theories. The one we will use here to explain is the two-factor theory otherwise known as Schachter-Singer theory. It's the best way to look at what is going on with how tranquilliser affect emotion.

Explanation: There are two ways emotion is formed. First one is the physiological reaction such as heart beat, and there is also the cognitive reactions which is usually subjective based in what someone is experiencing like fear, anger, excitement etc, so the nervous system gives off physiological(active) reaction that causes a subjective (cognitive) feelings such as fear and anxiety. The tranquilliser inhibit the physiological reaction in one factor of the cognitive reactions which shows the actual emotion.

However, the cannon-Bard theory suggest arousal and emotions occurred the same time, which makes it difficult in explaining emotion-reducing effect.

Hope this helps.

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The height at which the mass will be lifted is; 3 meters

<h3>How to utilize efficiency of a machine?</h3>

Formula for efficiency is;

η = useful output energy/input energy

We are given

η = 60% = 0.6

Input energy = 4 KJ = 4000 J

Thus;

0.6 = useful output energy/4000

useful output energy = 0.6 * 4000

useful output energy = 2400 J

Work done in lifting mass(useful output energy) = force * distance moved

Useful output energy = 800 * h

where h is height to lift mass

Thus;

800h = 2400

h = 2400/800

h = 3 meters

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1 year ago
Identify and describe the three stages of a life cycle analysis.
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2 years ago
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Convert 850 nm wavelength into frequency, eV, wavenumber, joules and ergs.
BabaBlast [244]

Answer:

Frequency = 3.5294×10¹⁴ s⁻¹

Wavenumber = 1.1765×10⁶ m⁻¹

Energy = 2.3365x 10⁻¹⁹ J , 1.4579 eV , 2.3365x 10⁻¹² erg

Explanation:

Given the wavelength = 850 nm

1 nm = 10⁻⁹ m

So, wavelength is  850×10⁻⁹ m

The relation between frequency and wavelength is shown below as:

c = frequency × Wavelength

Where, c is the speed of light having value = 3×10⁸ m/s

So, Frequency is:

Frequency = c / Wavelength

Frequency=\frac {3\times 10^8\ m/s}{850\times 10^{-9}\ m}

Frequency = 3.5294×10¹⁴ s⁻¹

Wavenumber is the reciprocal of wavelength.

So,

Wavenumber = 1 / Wavelength  = 1 / 850×10⁻⁹ m

Wavenumber = 1.1765×10⁶ m⁻¹

Also,

Energy=h\times frequency

where, h is Plank's constant having value as 6.62x 10⁻³⁴ J.s

So,

Energy = 6.62x 10⁻³⁴ J.s × 3.5294×10¹⁴ s⁻¹

Energy = 2.3365x 10⁻¹⁹ J

Also,

1 J = 6.24×10¹⁸ eV

So,

Energy = 2.3365x 10⁻¹⁹ × 6.24×10¹⁸ eV

Energy = 1.4579 eV

Also,

1 J = 10⁷ erg

So,

Energy = 2.3365x 10⁻¹⁹ × 10⁷ erg

Energy = 2.3365x 10⁻¹² erg

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Answer:

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