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ivolga24 [154]
4 years ago
8

Tranquilizing drugs that inhibit sympathetic nervous system activity often effectively reduce people's subjective experience of

intense anger or anxiety. Use one of the major theories of emotion to account for the emotion-reducing effects of such tranquilizers. Which theory of emotion would have the greatest difficulty explaining these effects? Why?
Engineering
1 answer:
bagirrra123 [75]4 years ago
6 0

Answer: There are different types of emotion theories. The one we will use here to explain is the two-factor theory otherwise known as Schachter-Singer theory. It's the best way to look at what is going on with how tranquilliser affect emotion.

Explanation: There are two ways emotion is formed. First one is the physiological reaction such as heart beat, and there is also the cognitive reactions which is usually subjective based in what someone is experiencing like fear, anger, excitement etc, so the nervous system gives off physiological(active) reaction that causes a subjective (cognitive) feelings such as fear and anxiety. The tranquilliser inhibit the physiological reaction in one factor of the cognitive reactions which shows the actual emotion.

However, the cannon-Bard theory suggest arousal and emotions occurred the same time, which makes it difficult in explaining emotion-reducing effect.

Hope this helps.

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Explain how assembly line change manufacturing include your thoughts on how Quality control can be inserted into the assembly li
Pani-rosa [81]
An assembly line is a manufacturing process in which interchangeable parts are added to a product in a sequential manner to create an end product. In most cases, a manufacturing assembly line is a semi-automated system through which a product moves. At each station along the line some part of the production process takes place. The workers and machinery used to produce the item are stationary along the line and the product moves through the cycle, from start to finish.
8 0
3 years ago
Find the Rectangular form of the following phasors?
almond37 [142]

Answer:

The angles are missing in the question.

The angles are :

45,     30,    60,     90,    -34,     -56,      20,     -42,  -65,    -15

P=10, P=5,  P=25, P=54, P=65, P=95, P=250, P=8, P=35, P=150

Explanation:

1. P = 10,   θ = 45°  rectangular coordinates

x = r cosθ  ,   y = r sinθ

So, rectangular form is x + iy

x = P cosθ = 10 cos 45°

  = 7.07

y =P sinθ = 10 sin 45°

  = 7.07

Therefore, rectangular form

x + iy = 7.07 + i (7.07)

2. P = 5 , θ = 30°

x = 5 cos  30° = 4.33

y = 5 sin  30° = 2.5

So, (x+iy) = 4.33 + i (2.5)

3. P = 25 , θ = 60°

x = 25 cos  60° = 12.5

y = 25 sin  60° = 21.65

So, (x+iy) = 12.5 + i (21.65)

4. P = 54 , θ = 90°

x = 54 cos  90° = 0

y = 54 sin  90° = 54

So, (x+iy) = 0+ i (54)

5. P = 65 , θ = -34°

x = 65 cos  (-34°) = 53.88

y = 65 sin  (-34°) = -36.34

So, (x+iy) = 53.88 - i (36.34)

6. P = 95 , θ = -56°

x = 95 cos  (-56)° = 53.12

y = 95 sin  (-56)° = -78.75

So, (x+iy) = 53.12 - i (78.75)

7. P = 250 , θ = 20°

x = 250 cos  20° = 234.92

y = 250 sin 20° = 85.5

So, (x+iy) = 234.92 + i (85.5)

8. P = 8 , θ = (-42)°

x = 8 cos  (-42)° = 5.94

y = 8 sin  (-42)° = -5.353

So, (x+iy) = 5.94 - i (5.353)

9. P = 35 , θ = (-65)°

x = 35 cos  (-65)° = 14.79

y = 35 sin  (-65)° = -31.72

So, (x+iy) = 14.79 - i (31.72)

10. P = 150 , θ = (-15)°

x = 150 cos  (-15)° = 144.88

y = 150 sin  (-15)° = -38.82

So, (x+iy) = 144.88 - i (38.82)

6 0
3 years ago
If a light draws 220 watts on a 120 volt circuit, how many amperes of electricity is it using?
vazorg [7]

Answer:

About 1.84 amperes

Explanation:

Since calculating amperes is dividing w/v, we can divided 220 by 120.

220/120 = 1.83333333333

Which can be rounded to:

1.84

8 0
3 years ago
Four eight-ohm speakers are connected in parallel to an audio power amplifier. The amplifier can supply a maximum driver output
Vera_Pavlovna [14]

Answer:

112.5 watts

Explanation:

The output voltage (V) = 15 volts

The equivalent resistance for the speakers connected in parallel (R_T) is gotten by using the formula:

\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4}\\\\But\ R_1=R_2=R_3=R_4=8\ ohm\\\\\frac{1}{R_T} =\frac{1}{8} +\frac{1}{8} +\frac{1}{8} +\frac{1}{8} \\\\\frac{1}{R_T} =\frac{1+1+1+1}{8} \\\\\frac{1}{R_T} =\frac{4}{8} \\\\R_T=\frac{8}{4} \\\\R_T=2\ ohm

The current flowing through the amplifier (I) is:

I = V / R_T = 15 / 2 = 7.5 A

The audio power (P) when outputting this maximum voltage is given by:

P = V² / R_T = I²R_T. Therefore:

P = V² / R_T = 15² / R_T = 112.5 watts

6 0
3 years ago
A) A cross-section of a solid circular rod is subject to a torque of T = 3.5 kNâ‹…m. If the diameter of the rod is D = 5 cm, wha
Alisiya [41]

Answer:

\tau_{max}  = 142.6 MPa

T = 1536.8 N m

Explanation:

Given data:

Torque = 3.5 k N m = 3.5*10^3 N.m

Diameter D = 5 cm = 0.05 m

a) from torsional equation we have

\frac[T}{J_{solid}} = \frac{\tau_{max}}{D/2}

\frac{T}{\pi/32 D^4} = \frac{\tau_{max}}{D/2}

solving for \tau_{max}

\tau_{max} = \frac{16 T}{\pi D^3} =\frac{16 \times 3.5*10^3}{\pi 0.05^3}

\tau_{max}  = 142.6 MPa

B)

\tau = 37 MPa = 37 \times  10^6 Pa

D_i = 4.5 cm = 0.045 m

D_o = 6.5 cm = 0.065 m

\frac{T}{J_{hollow}} = \frac{\tau_{max}}{D_o /2}

\frac{T}{(\pi/32) (0.065^4 - 0.045^4)} =\frac{37*10^6}{0.065/2}

T = 1536.8 N m

7 0
4 years ago
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