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Setler [38]
3 years ago
8

The electron beam in a TV picture tube carries 1015 electrons per second. As a design engineer, determine the voltage needed to

accelerate the electron beam to achieve 4 W.
Engineering
1 answer:
leonid [27]3 years ago
6 0

Answer:

The voltage needed to accelerate the electron beam is 2.46 x 10^16 Volts

Explanation:

The rate of electron flow is given as:

q = 1015 electrons per second

The total current is given by:

Total Current = (Rate of electron flow)(Charge on one electron)

Total Current = I = (1015 electrons/s)(1.6 x 10^-19 C/electron)

I = 1.624 x 10^-16 A

Now, we know that electric power is given as:

Electric Power = Current x Voltage

P = IV

V = P/I

V = 4 W/1.624 X 10^-16 A

<u>V = 2.46 x 10^16 Volts</u>

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andrew-mc [135]

Answer:

We choose PTFE

Explanation:

Attached are the modulus density and modulus strength chart.

Due to its young modulus, the density is near 0.5 GPa, as seen in the chart and support water gliding. The PTFE density is between 1 and 10 Mg / cubic meter (see module and chart of density), and the resistance is between 10 and 100 Mpa (see module and chart of strength). Therefore, the finest ploymer will be PTFE that meets the requirements.

8 0
3 years ago
A hollow, spherical shell with mass 2.00kg rolls without slipping down a slope angled at 38.0?.
mezya [45]

Answer:

\mu = 0.31

Explanation:

Given data:

mass = 2.00 kg

slope angle = 38.0

From figure

balancing force

mgsin\theta - f = ma   .....1

Balancing torque

F_R = \frac{2}{3} mR^2 \alpha ......2

for pure rolling

\alpha  = \frac{a}{R}

F = \frac{2}{3} ma

from 1 and 2nd equation

mgsin\theta - \frac{2}{3}ma =  ma

mgsin\theta = \frac{5}{3} ma

a = \frac{3}{5} g sin\theta

 = \frac{3\theta 9.8 sin 38}{5} = 3.62 m/s^2

F =\mu N

   = \frac{2}{3} ma

   = \frac{2}{3} 2\times 3.62 = 4.83 N

N =normal force =  mgsin\theta = 2 \times 9.8 sin 38 = 15.44 N

\mu \times 15.44 = 4.83

solving for  coefficent of friction we get

\mu = 0.31

4 0
3 years ago
Silicon chips are used primarily in ?
VMariaS [17]

Answer:

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hjlf

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Explanation:

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