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Zigmanuir [339]
3 years ago
10

The human circulatory system consists of a complex branching pipe network ranging in diameter from

Engineering
1 answer:
Stels [109]3 years ago
8 0

Answer: the average velocity decreases

Explanation:

From the provided data we have:

Vessel    avg. diameter[mm] number

Aorta                 25.0                   1

Arteries             4.0                    159

Arteioles           0.06                 1.4*10^7

Capillaries         0.012               2.9*10^9

from the information, let \hat{m} be the mass flow rate, \rho is density, n number of vessels, and A is the cross-section area for each vessel

the flow rate is constant so it is equal for all vessels,

The average velocity is related to the flow rate by:

\hat{m} = v* \rho * A * n

we clear the side where v is in:

v = \frac{\hat{m}}{\rho A n}

area is π*R^2 where R is the average radius of the vessel (diameter/2)

we get:

v = \frac{\hat{m}}{\rho \pi R^2 n}

you can directly see in the last equation that if we go from the aorta to the capillaries, the number of vessels is going to increase ( n will increase and R is going to decrease ) . From the table, R is significantly smaller in magnitude orders than n, therefore, it wont impact the results as much as n. On the other hand, n will change from 1 to 2.9 giga vessels which will dramatically reduce the average blood velocity

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The barrel of a bicycle tire pump becomes quite warm during use. Explain the mechanisms responsible for the temperature increase
Alexeev081 [22]

Answer:

The air heats up when being compressed and transefers heat to the barrel.

Explanation:

When a gas is compressed it raises in temperature. Assuming that the compression happens fast and is done before a significant amount of heat can be transferred to the barrel, we could say it is an adiabatic compression. This isn't exactly true, it is an approximation.

In an adiabatic transformation:

P^{1-k} * T^k = constant

For air k = 1.4

SO

P0^{-0.4} * T0^{1.4} = P1^{-0.4} * T1^{1.4}

T1^{1.4} = \frac{P1^{0.4} * T0^{1.4}}{P0^{0.4}}

T1^{1.4} = \frac{P1}{P0}^{0.4} * T0^{1.4}

T1 = T0 * \frac{P1}{P0}^{0.4/1.4}

T1 = T0 * \frac{P1}{P0}^{0.28}

SInce it is compressing, the fraction P1/P0 will always be greater than one, and raised to a positive fraction it will always yield a number greater than one, so the final temperature will be greater than the initial temperature.

After it was compressed the hot air will exchange heat with the barrel heating it up.

5 0
3 years ago
A treatment plant being designed for Cynusoidal City requires an equalization basin to even out flow and BOD variations. The ave
sineoko [7]

Answer:

The size of equalization basin is 6105.6 m³

Explanation:

The average flow is:

flow = ∑flow/n = 9.788/24 = 0.408 m³/s

Where n is the number or observations.

The inflow volume is:

V_{inflow} =Q*t

where t is the time interval

V_{inflow} =0.446(1*3600)=1605m^{3}

in the same way it is calculated the inflow volume for each observation

The outflow volume is:

V_{out} =Q_{out} *t=0.4*(1*3600)=1400m^{3}

The volume of flow is:

ds=V_{inflow} -V_{out} =1605-1400=205m^{3}

in the same way it is calculated the volume of flow for each observation. According to the file attach, the highest volume is 6105.6 m³

Download pdf
6 0
4 years ago
Two technicians are discussing hand tool use. Technician A says that a 6-point wrench is easier to use in tight places than a 12
Mila [183]

Answer:

<em>Technician B says that a ratchet is used to loosen fasteners that are very tight.</em>

Explanation:

A ratchet is a common wrench device with a fastener component. A ratchet wrench is an essential tool that is used to fasten or loosen nuts and bolts.

8 0
3 years ago
Read 2 more answers
To be safe, the engineers making the ride want to be sure the normal force does not exceed 1.8 times each persons weight - and t
Yuri [45]

Answer:

μ = 0.55

Explanation:

Given that

Normal weight = 1.8 x weight of person

N= 1.8 mg

We know that friction force Fr

Fr= μ N

μ=Coefficient of friction

N=Normal force

To find  μ We have to equate friction and gravity force

Fr= Wt

μ N = m g

μ  x 1.8 m g = m g

μ = 0.55

So the coefficient of friction will be 0.55.

5 0
3 years ago
A bar of 75 mm diameter is reduced to 73mm by a cutting tool while cutting orthogonally. If the mean length of the cut chip is 7
barxatty [35]

Answer:

r=0.31

Ф=18.03°

Explanation:

Given that

Diameter of bar before cutting = 75 mm

Diameter of bar after cutting = 73 mm

Mean diameter of bar d= (75+73)/2=74 mm

Mean length of uncut chip = πd

Mean length of uncut chip = π x 74 =232.45 mm

So cutting ratio r

Cutting\ ratio=\dfrac{Mean\ length\ of cut\ chip}{Mean\ length\ of uncut\ chip}

r=\dfrac{73.5}{232.45}

  r=0.31

So the cutting ratio is 0.31.

As we know that shear angle given as

tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }

Now by putting the values

tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }

tan\phi =\dfrac{0.31cos15 }{1-0.31sin15 }\

  Ф=18.03°

So the shear angle is 18.03°.

4 0
4 years ago
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