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FinnZ [79.3K]
3 years ago
10

The cost of a disc holder is 25p.

Mathematics
2 answers:
elixir [45]3 years ago
5 0
If you would like to know what is the greatest number of compact disc holders John can buy for £15, you can calculate this using the following steps:

£15 / 25p = £15 / £0.25 = 15 / 0.25 = 60 compact disc holders

Result: The greatest number of compact disc holders would be 60.
34kurt3 years ago
4 0
Let us first look at all the important information’s that are provided in the question. Based on these details the answer to the question can be easily found.
Amount that John can spend = 15 pounds
Cost of each disc holder = 25 p
                                        = 0.25 pounds
Then
Maximum number of discs that John can buy = 15/0.25
                                                                         = 60
So John can buy 60 discs.<span>Hope this is what you were looking for.

</span>


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Dan takes an airplane to visit his parents. He pays the airline a total of $450. The cost of the ticket is $315. The airline als
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Start with the total amount Dan paid and subtract the part of the payment that is for the ticket.

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2 years ago
A certain number of sixes and nines is added to give a sum of 126; if the number of sixes and nines is interchanged, the new sum
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Answer:

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Original number of nines = 10

Step-by-step explanation:

We are told in the question that:

A certain number of sixes and nines is added to give a sum of 126

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the number of sixes = a

the number of nines = b

Hence:

6 × a + 9 × b = 126

6a + 9b = 126.....Equation 1

If the number of sixes and nines is interchanged, the new sum is 114.

For this second part, because it is interchanged,

Let us represent

the number of sixes = b

the number of nines = a

6 × b + 9 × a = 114

6b + 9a = 114.......Equation 2

9a + 6b = 114 .......Equation 2

6a + 9b = 126.....Equation 1

9a + 6b = 114 .......Equation 2

We solve using Elimination method

Multiply Equation 1 by the coefficient of a in Equation 2

Multiply Equation 2 by the coefficient of a in Equation 1

6a + 9b = 126.....Equation 1 × 9

9a + 6b = 114 .......Equation 2 × 6

54a + 81b = 1134 ........ Equation 3

54a + 36b = 684.........Equation 4

Subtract Equation 4 from Equation 3

= 45b = 450

divide both sides by b

45b/45 = 450/45

b = 10

Therefore, since the original the number of nines = b,

Original number of nines = 10

Also, to find the original number of sixes = a

We substitute 10 for b in Equation 1

6a + 9b = 126.....Equation 1

6a + 9 × 10 = 126

6a + 90 = 126

6a = 126 - 90

6a = 36

a = 36/6

a = 6

Therefore, the original number of sixes is 6

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