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3 years ago

The cost of a disc holder is 25p.

2 answers:

5 0

If you would like to know what is the greatest number of compact disc holders John can buy for £15, you can calculate this using the following steps:

£15 / 25p = £15 / £0.25 = 15 / 0.25 = 60 compact disc holders

Result: The greatest number of compact disc holders would be 60.

34kurt3 years ago

4 0

Let us first look at all the important information’s that are provided in the question. Based on these details the answer to the question can be easily found.
Amount that John can spend = 15 pounds
Cost of each disc holder = 25 p
= 0.25 pounds
Then
Maximum number of discs that John can buy = 15/0.25
= 60
So John can buy 60 discs.Hope this is what you were looking for.

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Chandler needed 10 gallons of gas last week. This week, Chandler ended up needing 60% more than that amount.How much gas is that

timama [110]

Answer:

16 gallons total

Step-by-step explanation:

60% of 10 is 6

6 plus the original 10 is 16

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3 years ago

Read 2 more answers

I NEED HELP PLEASE ! :)

dedylja [7]

We can write a proportion to resemble the problem;

AE/ED = AB/BC

AE = 9

ED = 6

AB = x

BC = 10

Substitute with the given values.

9/6 = x/10

9/6 * 10 = x/10 * 10

90/6 = x

15 = x

Therefore, the answer is 15.

Best of Luck!

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4 years ago

Read 2 more answers

Truck -Rite Rentals rents trucks at daily rate of $49.95 plus 39 cents per mile. concert Productions has budgeted $100 for renti

Sergio039 [100]

$100 - $49.95 = $50.05
You have $100, and just renting costs $49.95, leaving $50.05 left.
$50.05 / $0.39 = 128.3
Out of your money left ($50.05) you divide my how much it costs in a day, to get how many miles you can go.

The answer is 128.3, but if you were going a round trip (there and back) you would do 128.3 / 2 = 64.16, meaning you can go 64 miles and come back, all for a hundred dollars (still 128 miles in total though)

6 0

3 years ago

Dexter collected data from his classmates on whether they prefer hamburgers or hotdogs.

algol13

C) More girls than boys prefer hamburgers over hotdogs.

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3 years ago

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A normal window is constructed by adjoining a semicircle to the top of an ordinary rectangular window, (see figure ) The perimet

Dima020 [189]

Let's find the perimeter of the window.

The bottom side is $x$ . The left and right sides make $2y$ .
The perimeter of a circle is $2\pi r$ , so the perimeter of a semicircle must be $\pi r$ , The radius is $\frac{1}2x$ , so that gives $\frac{1}2\pi x$ for the curve. All of that is equal to 12.

$x+2y+\frac{1}2\pi x=12$

We only want to use one variable to create the area formula, so let's solve for $y$ .

$2y=12-x-\frac{1}2\pi x$

$y=6-\frac{1}2x-\frac{1}4\pi x$

Now that we have a value for $y$ in terms of $x$ , we can find the area in terms of $x$ .

The area of the rectangle is going to be $xy$ , which then becomes

$A_r=x(6-\frac{1}2x-\frac{1}4\pi x$

$A_r=6x-\frac{1}2x^2-\frac{1}4\pi x^2$

The area of the semicircle is going to be $\frac{1}2\pi r^2$ .

Since $r=\frac{1}2x$ , $A_{sc}=\frac{1}2\pi (\frac{1}2x)^2$ .

$A_{sc}=\frac{1}2\pi \frac{1}4x^2$

$A_{sc}=\frac{1}8\pi x^2$

Now let's add the areas of the rectangle and semicircle.

$A=A_r+A_{sc}$

$A=6x-\frac{1}2x^2-\frac{1}4\pi x^2+\frac{1}8\pi x^2$

$A=6x-\frac{1}2x^2-\frac{1}8\pi x^2$

If you wanted to factor out $\frac{1}8$ like you did, this would become

$\boxed{A(x)=\frac{1}8(48x=4x^2-\pi x^2)}$

Now what we want to do is find what $x$ is when $A$ is at its highest point, Once we have the value for $x$ we can also find the value for $y$ , of course.

Let's put our equation in the general form of a quadratic.

$A(x)=(-\frac{1}2-\frac{1}8\pi )x^2+6x$

Now we can use the vertex formula $x=\frac{-b}{2a}$ .
( $a$ and $b$ refer to $ax^2+bx+c$ .)

$x=\frac{-6}{2(-\frac{1}2-\frac{1}8\pi)}$

$x=\frac{-6}{-\frac{1}4\pi -1}$

$x=\frac{-24}{-\pi -4}$

$\boxed{x=\frac{24}{\pi +4}}$

Now let's plug that in for $y=6-\frac{1}2x-\frac{1}4\pi x$ .

Since our final answers are in decimal form and not exact form, we can make our lives a little easier here and just use $x\approx3.36059492$ .

$y\approx6-\frac{1}2(3.36059492)-\frac{1}4\pi(3.36059492)$

 $y\approx6-(1.68029746+2.63940507809)$

 $\boxed{y\approx1.68029746191}$

Let's take our answers for $x$ and $y$ and round to 2 decimal places.

$\boxed{x\approx 3.36\ ft}$

$\boxed{y\approx 1.68\ ft}$

3 0

3 years ago