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trapecia [35]
2 years ago
13

Find the smallest value of k, such that 693k is a perfect cube.

Mathematics
2 answers:
QveST [7]2 years ago
8 0

Answer:

MGMHMHMHNHMMJMMMH

BSEHEJR

Jet001 [13]2 years ago
3 0

Answer:

\frac{8^3}{693}=\frac{512}{693}\quad \left(\mathrm{Decimal:\quad }\:0.73881\dots \right)

Step-by-step explanation:

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