3 years ago

Find the smallest value of k, such that 693k is a perfect cube.

Mathematics

2 answers:

QveST [7]3 years ago

8 0

Answer:

MGMHMHMHNHMMJMMMH

BSEHEJR

Jet001 [13]3 years ago

3 0

Answer:

$\frac{8^3}{693}=\frac{512}{693}\quad \left(\mathrm{Decimal:\quad }\:0.73881\dots \right)$

Step-by-step explanation:

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