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finlep [7]
3 years ago
14

Encuentra el cociente ??​

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0

For this case we must find the quotient of the following expression:

\frac {(- 8x ^ 2 * y) (- 7x ^ 5 * y ^ 3)} {- 2x ^ 2 * y ^ 3}

We can rewrite the expression as:

(We take into account that- * - = +)

\frac {56x ^ 2 * y * x ^ 5 * y ^ 3} {- 2x ^ 2 * y ^ 3} =

By definition of multiplication of powers of the same base, we place the same base and add the exponents:

\frac {56x ^ {2 + 5} * y ^ {1 + 3}} {- 2x ^ 2 * y ^ 3} =\\\frac {56x ^ {7} * y ^ {4}} {- 2x ^ 2 * y ^ 3} =

By definition of division of powers of the same base, we place the same base and subtract the exponents:

-28x^{ 7-2} * y^{ 4-3} =\\-28x ^ 5 * y

Answer:

-28x ^ 5 * y

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Total crackers on the plate are 12

Step-by-step explanation:

Manuel ate crackers = \frac{1}{3}

His brother ate crackers = \frac{1}{4}

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We need to find how many crackers were there on the plate.

Let x be the total crackers on the plate

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