All categories

3 years ago

9. The table below shows the change in a stock price over a period of a week. If 12 shares of

Mathematics

1 answer:

ankoles [38]3 years ago

4 0

Answer:

$ 6.24

Step-by-step explanation:

(16.87 - 16.35) x 12 = 6.24

You might be interested in

I need help, please

oksian1 [2.3K]

Yes, a rhombus is a rectangle if it has a similar shape of a square.Hope that helped

6 0

3 years ago

Find the equation of the line passes through (-3,-4) and whose slope is 3/2 in slope intercept form. (Algebra 2 or Geometry)

ioda

Hey there! I'm happy to help!

Slope intercept form is y=mx+b, where m is the slope and b is the y-intercept. We already have the slope, so our equation so far is y=3/2x+b. We just need to find the b for it to be complete.

To do this, we plug in a point on the line and solve for b. We have a point (-3,-4), so let's use it and solve.

-4=3/2(-3)+b

Undo parentheses.

-4=-9/2+b

Add 9/2 to both sides

b=1/2

Therefore, our equation is y=3/2x+1/2.

Have a wonderful day! :D

4 0

3 years ago

What is the factored from for -2r-6 PLEASE HELP! WILL MARK BRAINLIEST

Katarina [22]

Answer:

-2(r+3)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Vertex of f(x) = 1/2(x-2)^2-3

AlekseyPX

Vertex is (2,-3). H (which is 2) sign is always opposite and k stays the same

3 0

3 years ago

Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec

expeople1 [14]

Answer:

$cot x = \frac{cos x}{sin x}$

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

$cos x cot x + sin x$

We know from math properties that the definition for cot is $cot x = \frac{cos x}{sin x}$

If we use this definition we got:

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

Now we can use the following identity:

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

4 0

4 years ago