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Hitman42 [59]
3 years ago
14

Rewrite each expression more simply: 3y + 8y

Mathematics
1 answer:
ELEN [110]3 years ago
6 0
Since they both have the same variable(y) you can add them together like a regular math problem. So:
3y+8y=11y
So your final answer would be 11y.
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as part of her shop class, Jules made the figure below out of pieces of wood. how much spave does the figure she made take up?
OlgaM077 [116]
I suppose you want to find the Volume of this Figure.

you can separate it into two rectangular prisms
one that is 6 by 9 by 24
and the other that is 6 by 9 by 30

you multiply the three numbers to get the volume of each rectangular prism.
6 * 9 * 24 = 1296
6 * 9 * 30 = 1620

then we add the two numbers we got to get the overall volume of the figure
1296 + 1620 = 2916

Therefore the Figure takes up 2916 cm^3 of space.
4 0
3 years ago
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Hey guys is this correct?
lutik1710 [3]

Answer:

Step-by-step explanation:

y e s , m e h  f r i e n d

6 0
2 years ago
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The figure below shows a straight line AB intersected by another straight line t:
BaLLatris [955]

When two straight lines intersect, the pairs of nonadjacent angles in opposite posi-tions are known as vertical angles.

If a segment AB is intersected by a transversal labeled t, then ∠1 and ∠3 and ∠2 and ∠4 are vertically angles formed by the transversal t on the segment AB.

Angles ∠1 and ∠2 can be described as adjacent and supplementary angles, so

m\angle 1+m\angle 2=180^{\circ}.

Angles ∠3 and ∠2 can be also described as adjacent and supplementary angles, so

m\angle 3+m\angle 2=180^{\circ}.

Subtract from the first equation the second equation:

m\angle 1+m\angle 2-(m\angle 3+m\angle 2)=180^{\circ}-180^{\circ},\\ m\angle 1-m\angle 3=0,\\ m\angle 1=m\angle 3.

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4 0
3 years ago
Need help somebody pleaseee
horsena [70]

Answer:

The second one I believe

8 0
3 years ago
What is the equation of the circle with center (0, 0) that passes through the point (-8, 3)?
77julia77 [94]

 

hello :<span>
<span>an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is :  x² +y² = 73</span></span>

7 0
4 years ago
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