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olga_2 [115]
4 years ago
8

I’ve tried 3 takes and just can’t seem to get it

Mathematics
2 answers:
Sonja [21]4 years ago
8 0
Hello!

First you have to make the fraction have the same denominator so they are related

You can multiply the 1 and the 3 in 1/3 by 5 to get 5/15

You can multiply the 2 and the 5 in 2/5 by 3 to get 6/15

So he painted 5/15 of his room with 6/15 cans of paint.

Next you have to find out how much more of the room that needs to be painted

You can multiply 5/15 by 3 to get 1 which is his whole room

Now you do 6/15 * 3 to see how much paint he needs

This gives us the answer of 18/15 which is equal to  1 and 1/6 cans of paint

 Hope this helps!
Rzqust [24]4 years ago
3 0
1/3 and 2/5 --> what we need is a least common denominator
(1/3)x5                     (2/5)x3
5/15 and 6/15
so he needs to paint his room two more times which will make the 5/15 become 15/15 
you start with 5/15 and you need to add "5/15" two more times which will make 15/15
so you do that to 6/15 
6/15+6/15+6/15=18/15=1 3/15 or 1 1/5 cans of paint ANSWER
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3 years ago
Given: PSTQ is a trapezoid. ST=4, PQ=25, PS=13, TQ=20 Find: Area of PSTQ.
babunello [35]

Answer:

  174 units²

Step-by-step explanation:

There are a few different ways you can find the altitude of the trapezoid. Consider the attached figure with some points and lines added. SQ' is parallel to TQ, so Q'Q = 4 and PQ' = 21. Based on the side length of PS = 13, you can <u>guess</u> that the height is 12. (5-12-13 is a commonly-used Pythagorean triple.) This would make PP' = 5, P'Q' = 16, and triangle SP'Q' have side lengths 12, 16, and 20, corresponding to a 3-4-5 right triangle multiplied by 4.

Another way to find the height is to use Heron's formula for the area of triangle PSQ'. The side lengths are 13, 20, 21, so the half-perimeter is 27 and the area is √(27(27-13)(27-20)(27-21)) = √(9²·14²) = 126. The base of the triangle, PQ', is 21, so the height is ...

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