Answer:
5 Green earrings
Step-by-step explanation:
Given that:
Total amount held = $51
Cost per pair of green earrings = $9
One time shipping fee = $6
How many pairs of green earrings did grace purchase?
Let the number of green earrings purchased = g
Then,
$9*g + $6 = $51
$9g + $6 = $51
$9g = $51 - $6
$9g = $45
g = $45 / $9
g = 5
Hence, the number of green earrings purchased = 5
Answer:
x= 3 +
, 3 -
Step-by-step explanation:
You use the quadratic formula to get x= 
Then you simplify and get the answers x= 3 +, 3 -
The median for city A is 4 because the bracket is 2, 3.5, 4, 4, 5, 5.5. The middle numbers are 4 which add to eight and divide by two to make 4. The median for city B is 5. 25 because the bracket is 3.5, 4, 5, 5.5, 6, and 6. The middle numbers are 5 and 5.5 which add to 10.5 and divide by two to make 5.25.
Answer: 1:50
The scale factor is 5/250 = 1/50
Answer:
Step-by-step explanation:
So in this example we'll be using the difference of squares which essentially states that: 
or another way to think of it would be: 
. So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:
Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:
So completely factored form is: 
I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because 
. and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: 
just something that might be useful in some cases.
