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brilliants [131]
3 years ago
13

Which change(in percent) is bigger :

Mathematics
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

Losing weight from 50lb to 40lb is a larger percent change.

That would be the equivalent of going from 100lb to 80lbs

Step-by-step explanation:

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A loan is borrowed for $1200 for 2 years at a compound interest of 6%. Interest is compounded annually. What is the compound amo
Kruka [31]

A = 1200(1 + 0.06)^2= 1348.32


5 0
3 years ago
Read 2 more answers
Need help please !!!
irina1246 [14]

sin^2 x + 4 sinx +3       3 + sinx

--------------------------  =  -------------------

cos^2 x                        1 - sinx


factor the numerator


(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

cos^2 x                        1 - sinx


cos^2 = 1-sin^2x

(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

1- sin^2x                       1 - sinx

factor the denominator

(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

(1-sinx ) (1+sinx)                   1 - sinx

cancel the common term (1+sinx)  and (sinx +1)

(sinx +3)                       3 + sinx

--------------------------  =  -------------------

(1-sinx )                           1 - sinx


reorder the first term

3+sinx                           3 + sinx

--------------------------  =  -------------------

(1-sinx )                           1 - sinx

3 0
3 years ago
Student records suggest that the population of students spends an average of 6.30 hours per week playing organized sports. The p
Ymorist [56]

Answer:

a) 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

b) 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

Step-by-step explanation:

To solve this question, it is important to know the Normal probability distribution and the Central Limit Theorem

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 6.3, \sigma = 2.1, n = 49, s = \frac{2.1}{\sqrt{49}} = 0.3

A) What is the chance HLI will find a sample mean between 5.5 and 7.1 hours?

This is the pvalue of Z when X = 7.1 subtracted by the pvalue of Z when X = 5.5.

By the Central Limit Theorem, the formula for Z is:

Z = \frac{X - \mu}{s}

X = 7.1

Z = \frac{7.1 - 6.3}{0.3}

Z = 2.67

Z = 2.67 has a pvalue of 0.9962

X = 5.5

Z = \frac{5.5 - 6.3}{0.3}

Z = -2.67

Z = -2.67 has a pvalue of 0.0038

So there is a 0.9962 - 0.0038 = 0.9924 = 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

B) Calculate the probability that the sample mean will be between 5.9 and 6.7 hours.

This is the pvalue of Z when X = 6.7 subtracted by the pvalue of Z when X = 5.9

X = 6.7

Z = \frac{6.7 - 6.3}{0.3}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

X = 5.9

Z = \frac{5.9 - 6.3}{0.3}

Z = -1.33

Z = -1.33 has a pvalue of 0.0918.

So there is a 0.9082 - 0.0918 = 0.8164 = 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

5 0
3 years ago
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Mandarinka [93]
Hey I can help. Do u still need it?
7 0
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Alex_Xolod [135]
Just remember  \sqrt{-1} = i

Sub in the numbers:
3 + \sqrt{-16} = 3+  \sqrt{16}\sqrt{-1} = 3 + 4i
7 0
3 years ago
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