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brilliants [131]
3 years ago
13

Which change(in percent) is bigger :

Mathematics
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

Losing weight from 50lb to 40lb is a larger percent change.

That would be the equivalent of going from 100lb to 80lbs

Step-by-step explanation:

You might be interested in
The US Census Bureau reported the US population to be approximately 308,000,000 in 2010. It also reported that 6.5% of the popul
Ivahew [28]
Given that the US population is approximately 308,000,000 in 2010 and that 6.5% of this population is under 5 years of age, we will know that number of children by multiplying 6.5% by 308,000,000. So the answer would be 20,020,000. So that is the number of children below 5 years old. Hope this helps.
3 0
2 years ago
Let P(x) = 3x³-ax+b. If P(1) = P(-1) and P(2)=16, find the values of a and b
kozerog [31]

P(1) = P(-1)

P(1) = 3 - a + b
P(-1) = -3 + a + b

-> 3 - a + b = -3 + a + b
-> 3 - a + b + 3 - a - b = 0
-> 6 - 2a = 0
-> a = 3.

P(2) = 24 - 2a + b -> 24 - (2a - b) = 16 -> 2a - b = 8
-> 6 - b = 8
b = -2.

So, a = 3 and b = -2

Recheck : P(1) = 3 - 3 + (-2) = -2
P(-1) = -3 + 3 + (-2) = -2 => P(1) = P(-1) (true)

P(2) = 24 - 6 + (-2) = 16.

6 0
2 years ago
in 1991, a gallup poll reported this percent to be 79%. using the data from this poll, test the claim that the percent of driver
snow_lady [41]

We reject our null hypothesis, H₀, at a level of significance of =0.01 since the P-value is less than that threshold. There is compelling statistical data to indicate that since 1991, the proportion of drivers who love driving has decreased.

Given,

The Pew Research Center recently polled n=1048 U.S. drivers and found that 69% enjoyed driving their automobiles.

In 1991, a Gallup poll reported this percentage to be 79%. using the data from this poll, test the claim that the percentage of drivers who enjoy driving their cars has declined since 1991.

To report the large-sample z statistic and its p-value,

Null hypothesis,

H₀ : p = 0.79

Alternative hypothesis,

Ha : p < 0.79

Level of significance, α = 0.01

Under H₀

Test statistic,

Z_0= \frac{\hat p - p}{\sqrt{\frac{p(1-p)}{n} }  }

Z₀ = -7.948

The alternative hypothesis(Ha) is left-tailed, so the P-value of the test is given by

P-value = P(z <-7.945)

            = 0.000     (from z-table)

Since the P-value is smaller than given level of significance, α=0.01 we reject our null hypothesis, H₀, at α=0.0.1 level Strong statistical evidence to conclude that the percentage of drivers who enjoy driving their cars has declined since 1991.

To learn more about hypothesis click here:

brainly.com/question/17173491

#SPJ4

5 0
1 year ago
Please help me first person will get brainliest!!
olganol [36]

Answer:

6w-60x+6

Step-by-step explanation:

6(w-10x+1)

6w+6(-10)+6*1

6w-60x+6

8 0
2 years ago
Find the distance between the points (2,1), (-3,6)
topjm [15]

Answer:

5 times the square root of 2 or 7.071

Step-by-step explanation:

Hope it helps!

5 0
3 years ago
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