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galina1969 [7]
3 years ago
8

PLS HELP ASAP

Mathematics
2 answers:
REY [17]3 years ago
8 0
The first drop box answer is A. The second one is about 18,000
Maru [420]3 years ago
5 0

Function <span>A </span>shows the best fit for the scatter plot.

<span>Based on the scatter plot, we can predict that in the ninth year the population of black toads in the forest will be</span><span> about 18000</span>


You might be interested in
In a chess variant, a "lord" can move one space at a time, either upward, or to the right, or diagonally up and to the right. ho
valentina_108 [34]

There are 48639 ways for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard

<h3>Further explanation</h3>

The probability of an event is defined as the possibility of an event occurring against sample space.

\large { \boxed {P(A) = \frac{\text{Number of Favorable Outcomes to A}}{\text {Total Number of Outcomes}} } }

<h2>Permutation ( Arrangement )</h2>

Permutation is the number of ways to arrange objects.

\large {\boxed {^nP_r = \frac{n!}{(n - r)!} } }

<h2>Combination ( Selection )</h2>

Combination is the number of ways to select objects.

\large {\boxed {^nC_r = \frac{n!}{r! (n - r)!} } }

Let us tackle the problem.

This problem is similar to Pascal Triangle.

The Lord can move to the right or up in one way only.

We can put "1" in each box on the bottom and left to represent 1 possible movement.

To get the possibility of movement to another box, we will add the possibility of movement to the left, right, and diagonal squares as shown in Figure 1.

This process is repeated for the next box as shown in Figure 2.

Finally, after this process is repeated until the top right box, we get the results as shown in Figure 3.

There are 48639 ways for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard.

<h3>Learn more</h3>
  • Different Birthdays : brainly.com/question/7567074
  • Dependent or Independent Events : brainly.com/question/12029535
  • Mutually exclusive : brainly.com/question/3464581

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Probability

Keywords: Probability , Sample , Space , Six , Dice , Die , Binomial , Distribution , Mean , Variance , Standard Deviation

7 0
3 years ago
An arc of length 30 meters is formed by a central angle A on a circle of radius 15. The measure of A in degrees (to two decimal
Iteru [2.4K]
An arc of length 30 m : l = 30 m.
r = 15 m,  ∠ A = ?
Formula for the length of an arc is:
 l = r π A / 180°  ( where A is the central angle )
A = l · 180 / r π = ( 30 · 180 ) / ( 15 · 3.1415926 ) = 114.43 °
This is very close to your result. 
3 0
3 years ago
Read 2 more answers
A geologist has collected 5 specimens of basaltic rock and 7 specimens of granite. The geologist instructs a laboratory assistan
MaRussiya [10]

The rocks are chosen without replacement, which means that the hypergeometric distribution is used to solve this question. First we get the parameters, and then we answer the questions. From this, we get that:

  • E(X) = 5.25, Var(X) = 0.5966
  • P(X < 6) = 0.9545
  • P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

The mean and the variance are:

\mu = \frac{nk}{N}

\sigma^2 = \frac{nk(N-k)(N-n)}{N^2(N-1)}

We have that:

5 + 7 = 12 rocks, which means that N = 12

9 are chosen, which means that n = 9

7 are granite, which means that k = 7

Question a:

E(X) = \mu = \frac{9\times7}{12} = 5.25

Var(X) = \sigma^2 = \frac{9\times7(12-7)(12-9)}{12^2(12-1)} = 0.5966

Thus:

E(X) = 5.25, Var(X) = 0.5966

Question b:

Since there are only 5 specimens of basaltic rock, at least 9 - 5 = 4 specimens of granite are needed, which means that:

P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 4) = h(4,12,9,7) = \frac{C_{7,4}*C_{5,5}}{C_{12,9}} = 0.1591

P(X = 5) = h(5,12,9,7) = \frac{C_{7,5}*C_{5,4}}{C_{12,9}} = 0.4773

P(X = 6) = h(6,12,9,7) = \frac{C_{7,6}*C_{5,3}}{C_{12,9}} = 0.3181

Thus

P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.1591 + 0.4773 + 0.3181 = 0.9545

So P(X < 6) = 0.9545.

Question c:

5 of basaltic and 4 of granite: 0.1591 probability.

7 of granite is P(X = 7), in which

P(X = 7) = h(7,12,9,7) = \frac{C_{7,7}*C_{5,2}}{C_{12,9}} = 0.0455

0.1591 + 0.0455 = 0.2046, thus:

P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

A similar question is found at brainly.com/question/24008577

5 0
3 years ago
Can y’all help me in this pls
Darina [25.2K]

1. 1.5 and 3.5

2. both equations because they share these particular points

8 0
3 years ago
CAN YOU GUYS HELP ME ASAP PLEASE
Bess [88]
120 grains is = 2drahms because 2 drahms is equal to 120 grains (p=q, q=r)
3 0
2 years ago
Read 2 more answers
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