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tino4ka555 [31]
3 years ago
13

Here are four fractions labelled A, B, C and D.

Mathematics
1 answer:
yarga [219]3 years ago
4 0

Answer:

alright, where's the fraction?

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What is the product?<br><br> (6 r minus 1)(negative 8 r minus 3)
just olya [345]

Answer:

The required product is -48r^2-10r+3

Step-by-step explanation:

Consider the provided expression.

(6r-1)(-8r-3)

Open the parentheses.

6r\left(-8r\right)+6r\left(-3\right)+\left(-1\right)\left(-8r\right)+\left(-1\right)\left(-3\right)

-6\cdot \:8rr-6\cdot \:3r+1\cdot \:8r+1\cdot \:3

-48r^2-18r+8r+3

Add the like terms.

-48r^2-10r+3

Hence, the required product is -48r^2-10r+3

3 0
3 years ago
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2.) Find g(-3) for g(x) = 2x + 2
Gekata [30.6K]

Answer:

g(-3) = -4

Step-by-step explanation:

g(-3) = 2(-3) + 2

g(-3) = -6 +2

g(-3) = -4

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2 years ago
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