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yawa3891 [41]
3 years ago
11

Which is the equation of. Parabola with vertex (0,0) and focus (-3,0)

Mathematics
2 answers:
harina [27]3 years ago
4 0

Answer:

y² = -12x.

Step-by-step explanation:

Given  : Parabola with vertex (0,0) and focus (-3,0).

To find : Which is the equation of Parabola.

Solution : We have given that vertex (0,0) and focus (-3,0).

Standard form of parabolic equation  (y - k)² = 4p (x - h).

where the focus is (h + p, k) and vertex (h,k)

We can see h= 0 , k = 0,

h+p = -3

0 + p = -3

p = -3.

On plugging the values of h , k ,p

Then equation of parabola  (y - 0)² = 4(-3) (x - 0).

y² = -12x.

Therefore, y² = -12x.

11111nata11111 [884]3 years ago
4 0
<span>Which is the equation of. Parabola with vertex (0,0) and focus (-3,0)
</span>
Given:
<span>Vertex </span><span>=<span>(0,0)</span></span>
<span>Focus </span><span>=<span>(−3,0<span>)

From the formula:
</span></span></span><span>4p(x−h)=(y−k<span>)^2
</span></span><span>where p=3

substitute p=3 to the equation:
</span>4(3)(x−0)=(y−0)^2
<span>x^2=-12y
x=-y^2/12</span><span>


</span>

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