Answer:
One Solution
Step-by-step explanation:
Do distributive property
3k+6+3+7k=2k+4+3k
Combine like terms
10k+9=5k+4
Subtract 5k from 10k
5k+9=4
Subtract 9 from 4
5k=-5
Divide
k=-1
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Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.
The weight of the empty truck is 7 tons 254 pounds 10 ounces.
Step-by-step explanation:
Since we have given that
The gross weight of a truck containing 30 pigs = 8 tons 1123 pounds 6 ounces
Average weight of one pig = 95 pounds 10 ounces
Now,
We know that

So,

Similarly,

So, Net weight of the pigs in the truck

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.
Now, we'll find the weight of the empty truck is given by

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .