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gayaneshka [121]

3 years ago

13

Expressing cos^2x in terms of cos2x

1 answer:

bija089 [108]3 years ago

6 0

Rearrange
<span>2sin^2x = 1-Cos2x </span>

<span>Divide by 2 to isolate for sin^2x </span>
<span>sin^2x = (1-Cos2x)/2</span>

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Show in the diagram to the right which method could be used to prove ACD=ECD

Reika [66]

I think sss congruence

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3 years ago

Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22

madam [21]

The equation $x^{2} +y^{2} +z^{2} +2x-4y-6z=22$ in standard form looks like $(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}$ .

Given equation of sphere be $x^{2} +y^{2} +z^{2} +2x-4y-6z=22$ .

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like $x^{2} +y^{2} +z^{2} =r^{2}$ .

The given equation is $x^{2} +y^{2} +z^{2} +2x-4y-6z=22$ .

We have to break 22 which is in right side into various parts according to the left side of the equation.

$x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36$

$x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36$

$x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36$

$x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36$

$(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}$

Hence the equation $x^{2} +y^{2} +z^{2} +2x-4y-6z=22$ in standard form looks like $(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}$ .

Learn more about equations at brainly.com/question/2972832

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1 year ago

What is 15 plus 27? comon people, i need this answer fast, Linda this question is for u, so we can talk... ok

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Answer:

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Step-by-step explanation:

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3 years ago

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