There are

ways of selecting two of the six blocks at random. The probability that one of them contains an error is

So

has probability mass function

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.
The expected value of finding an error is then
Answer:

Step-by-step explanation:
Rational numbers, expressed as decimal numbers, are obtained from the operation of division between the integer of the numerator and the integer of the denominator. Then:

Answer:3/2
Step-by-step explanation:
He wants to buy flowers for me lol
Answer:
4,5,6
Step-by-step explanation:
*The sign of ≥ means that it must be greater or equal to 10 in this case
1). 3 isn't a possible solution due to 9 being less than 10
3+6_10
9_10
9<10
2). 4 is a possible solution due to the sum of 4 and 6 being equal to 10
4+6_10
10_10
10=10
3). 5 is a possible solution due to the sum of 5 and 6 being larger than 10
5+6_10
11_10
11>10
4).6 is a possible solution due to the sum of 6 and 6 being larger than 10
6+6_10
12_10
12>10
Hope this helped! (: