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harkovskaia [24]
3 years ago
12

Can you help me with 4 and 5 and 7 please please

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

Answer:

  4. Nelson: 14; Alison: 36

  5. May: 12; April: 18

  7. Student: 7; Instructor: 27   --   caveat emptor

Step-by-step explanation:

4. Quick answer: The time between Alison being 2 times her son's age (age ratio = 4:2) and 3 times her son's age is 11 years. That means each "ratio unit" stands for 11 years. 3 years ago, when Alison was 3 times her son's age, he was 11 and she was 33. Now, he is 14 and she is 36.

<em>Check</em>

In 8 years, he will be 22 and she will be 44, twice his age.

__

If you want to write a system of equations, you can use A for Alison's age and N for Nelson's age.

  A+8 = 2(N+8) . . . . relation of ages in 8 years

  A -3 = 3(N -3) . . . . relation of ages 3 years ago

We can equate expressions for A:

  2(N +8) -8 = A = 3(N -3) +3

  2N +8 = 3N -6

  14 = N

  A = 2(14 +8) -8 = 36

Alison is 36; Nelson is 14.

____

5. Quick answer: The sum of ages 6 years from now will be 36. Then April will be twice May's present age. That is, May's present age is 1/3 0f 36 = 12. April is 30 -12 = 18. Now, April is 18 and May is 12.

<em>Check</em>

10 years from now, April will be 28. That is 4 years more than 2·12 = 24.

__

Once again, you can write a system of equations:

  A + M = 30

  A +10 = 2M +4

Again, equating expressions for A, we have ...

  30 -M = A = (2M +4) -10

  36 = 3M . . . . . simplify, add M+6

  12 = M

  A = 30 -12 = 18

April is 18; May is 12.

_____

7. Makes no sense. The first sentence says the age difference is 20 years. The second sentence says the age difference is 5 years. It can't be both. Something is missing somewhere.

__

If we assume the word "twice" is missing, then the system of equations for Instructor and Student can be ...

  I = S + 20

  I + 8 = 2(S +8) +5

Substituting for I, we have ...

  S +20 +8 = 2S +16 +5

  7 = S . . . . . . subtract S+21

  I = 7+20 = 27

The instructor is 27, the student is 7.

<em>Check</em>

In 8 years, the instructor will be 35 and the student will be 15. At 35, the instructor will be 5 years more than twice the student's age.

__

We have essentially written our own problem statement here. Your problem statement, and your answer, may vary.

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Answer:

20 is to 56 as 3 is to x

20x= 8.2

5 0
3 years ago
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 80 minutes
mixer [17]

Answer:

0.02275

Step-by-step explanation:

We have been given that the time needed to complete a final examination in a particular college course is normally distributed with a mean of 80 minutes and a standard deviation of 10 minutes. We are asked to find the probability of completing the exam in one hour or less.

We know that 1 hour equals 60 minutes. First of all, we will find the z-score corresponding to 60 minutes.  

z=\frac{x-\mu}{\sigma}

z = z-score,

x = Sample score,

\mu = Mean,

\sigma = Standard deviation.

z=\frac{60-80}{10}

z=\frac{-20}{10}

z=-2

Now, we will use normal distribution table to find area under z-score of -2 as:

P(z< -2)

P(z< -2)=0.02275

Therefore, the probability of completing the exam in one hour or less is 0.02275.

7 0
3 years ago
How many times is 0.7m in 28m
astra-53 [7]
Solve:-

28 ÷ 0.7 = 40
28m ÷ 0.7m = 40

0.7 goes 40 times in 28m.
4 0
3 years ago
Read 2 more answers
.,..................................
Masteriza [31]
What do you want us to answer??

7 0
4 years ago
Help please <br> I need to pass my class
valina [46]

Answer:

look below

Step-by-step explanation:

thing to note:

sin = opposite/hypotenuse

cos = adjacent/hypotenuse

tan = opposite/adjacent

opposite= side across angle you are using

hypotenuse= side across 90 degree angle

adjacent= remaining side

angle B

sin = 6/10

cos = 8/10

tan = 6/8

angle C

sin = 8/10

cos = 6/10

tan = 8/6

hope that helped. let me know if you have any questions:)

3 0
3 years ago
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