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podryga [215]
3 years ago
5

Any one know this I’m stuck!

Mathematics
1 answer:
sammy [17]3 years ago
7 0

Answer:

i will have to say b

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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A hotel offers a reward program based on the number of night stayed. The function f(x) represents the number of free nights earn
iris [78.8K]

Answer:

a. A customer earns 1 free night per 10 nights stayed.  

Step-by-step explanation:

The missing function is:

f(x) = x/10  

The missing options are:

<em> a. A customer earns 1 free night per 10 nights stayed.  </em>

<em> b. A customer starts with 1 free night and then earns another free night after every 10 nights stayed. </em>

<em> c.A customer earns x – 10 free nights for every 10 nights stayed.  </em>

<em> d. A customer earns 10 free nights after x number of nights stayed. </em>

The function means that after a customer stayed 10 nights, a free night is earned. That is, replacing x = 10 into the function, we get:

f(10) = 10/10  = 1

which means 10 nights are equivalent to 1 free night.

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3 years ago
HURRY PLEASE!! find the lcm of 3x^2-6x-24 and 9x^2-36
Mrac [35]

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Step-by-step explanation:

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3 years ago
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The full question.the full question you were asking for ​
Svetlanka [38]

Answer:

I'm getting stuck by

= lim \:  \:  \:  \:  \:  \:   \frac{ {h}^{ \frac{1}{5} } }{h}  \\ h > 0

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2 years ago
The probability that a student pilot passes the written test for a private pilot's license is 0.7. what is the probability that
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<span>Probability = 0.063 Fourth try = 0.0973 Let X be the number of failed attempts at passing the test before the student passes. This is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7 and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p) xp. The probability P that the student passes on the third try means that there were x = 2 failed attempts or P = nb(2, ; 1, .7) = (.3)2 (.7) = 0.063 . The probability that the student passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤ 2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0 (.7) + (.3)1 (.7) + (.3)2 (.7) = 0.973 .</span>
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3 years ago
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