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kherson [118]
3 years ago
7

Please be kind and help me on this question. WARNING: only if your good at math thank you

Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0

Short Answer: The first three are absolutely true. Congruency is maintained if all you are doing is shifting the figure 8 spaces away. Since the figures are congruent, their corresponding parts are equal and the statements made are always true. That's the guiding principle.


A is true. See the short answer.


B is True. You have gone 8 units away. The distance between the old G and the new one is 8 units. This is not a congruency property but it is true because it is given. You haven't altered the shape or rotatated it.


C is true by conguency. You have just shifted things 8 units. You have maintained equality and you have maintained distance between corresponding parts.


That leaves D. If the figures are regular, that will be true. If they are not regular, non corresponding external angles cannot be guaranteed to be true.

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Please select the best answer from the choices provided
NeTakaya

we are given

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }

we can use exponent formula

a^n \cdot a^m=a^{n+m}

now, we can use this formula

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2^{\frac{1}{2}+\frac{1}{2} }

we can add exponent

and we get

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2^{\frac{1+1}{2} }

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2^{\frac{2}{2} }

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2^{1}

2^{\frac{1}{2}}\cdot 2^{\frac{1}{2} }=2

So, option-B.......Answer

8 0
3 years ago
Read 2 more answers
A pool of linen container 100 meters. three butete brought 15.75 meters, 22.50 meters and 12.25 meters respectively. how many me
Nitella [24]

Answer:

49.5 meters of linen were left after the sale.

Step-by-step explanation:

Given that there are 100 meters of linen

And 15.75, 22.50 and 12.25 meters are sold.

This means that the sold linen has to be added  to find the total linen sold.

And then the quantity of sold linen will be subtracted from 100 to find the meters of linen left.

Total\ linen\ sold = 15.75+22.50+12.25 = 50.5\ meters

Left linen will be:

=100-50.5 = 49.5

Hence,

49.5 meters of linen were left after the sale.

6 0
3 years ago
What percent of students answered 15 or more questions correctly?
Andrew [12]

Answer:

If I'm thinking right then the answer should be 5% ?

There's 8 students total if I'm correct?

2 people got 15.

2 people got 16.

1 person got 17.

2+2+1=5

2 person got 14.

1 person got 12.

2+1=3                        There's 8 students total. but the answer should be 5%.

4 0
3 years ago
A tangent to a circle at point A is given, and point A is an endpoint of a chord, which is the same length as radius of the circ
Nutka1998 [239]

Answer:

30°

Step-by-step explanation:

Call the other end of the chord point B and the center of the circle point O. Then triangle AOB is an equilateral triangle, since OA = OB = AB.

Angle OAB is the internal angle of that triangle, so is 60°. Since OA is perpendicular to the tangent line (makes an angle of 90°), The angle between the tangent line and the chord must be ...

90° - 60° = 30°

___

The other way you know this is that central angle AOB is 60°, and the tangent-to-chord angle is half that, or 30°.

_____

One way to remember the angle relationship between a tangent line and a chord is this:

Consider a point C on long arc AB. The measure of inscribed angle ACB is half the measure of central angle AOB, no matter where C is on the circle. (If C happens to be on the short arc AB, then central angle AOB is a reflex angle, but the relationship still holds.) Consider what happens when C approaches A. The angle at vertex C is still the same: 1/2 the measure of central angle AOB. This remains true even in the limit when points A and C become coincident and line AC is a tangent at point A.

6 0
3 years ago
What is the distance between (-2,2) and (4,-6) on coordinate plane
PtichkaEL [24]

Hey there!!

How do we find the distance between two coordinate points?

In order to find the distance, we use this formula :

\sqrt{( x2 - x1 )^{2} + (y2-y1)^{2}}

The given coordinates :

( -2 , 2 ) and ( 4 , -6 )

x2 = 4 and x1 = -2 ; y2 = -6 and y1 = 2

Now, plug in the values :

\sqrt{(4-(-2)^{2} + (-6-2)^{2}}

\sqrt{6^{2} + (-8)^{2}}

\sqrt{36 + 64}

\sqrt{100}

=50

Hence, the distance is 50 units.

Hope my answer helps!

3 0
4 years ago
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