Two angles are said to be supplementary if their sum is 180 degrees. So, if x and y are supplementary angles, the formula is
We know that one of the angles (say x) is 98. So, the equation updates to
If we want to solve for the other angle, we can simply subtract 98 from both sides to get
Ron should receive $7.98. Jerry and Steve each worked for 4 hours, while Ron was one hour late, so he worked for 3 hours. Together, they worked for 4*2+3=11 hours, receiving $29.25 in total. Each hour should be paid 29.25/11=2.66 dollars. Ron worked for three hours, so he should receive 3*2.66=7.98 dollars.
The expression which shows the total cost is 2.50+0.4x and the cost of riding 20 miles is $10.50.
Given a taxi charges $2.50 for the first mile and $0.40 for each mile
We are required to make an expression showing total cost and total cost of a 20 mile ride.
let the miles ride by tax be x.
Total cost of the product or service=Number of units*price of one units.
We have been given that $2.50 is fixed so we will not multiply our variable charge with $2.50 and multiply 0.40 with x.
So,the expression showing looks like 2.50+0.40x.
Now to find the cost when taxi travels 20 miles, we have to put x=20,
Cost=2.50+0.40*20
=2.50+(40*20)/100
=2.50+800/100
=2.50+8
=$10.50
Hence the expression which shows the total cost is 2.50+0.4x and the cost of riding 20 miles is $10.50.
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Answer:
Step-by-step explanation:
4.
distance=2436-(-1020)=2436+1020=3456 ft
5.
in two turns points=3-4=-1
in 6 turns=-1/2×6=-3 points
6.
-23+40=17
she had 17 dollars balance.
Answer:
The probability that a randomly selected adult is either overweight or obese is 0,688
Step-by-step explanation:
Probability that an american adult is overweight = 0,331
Probability that an american adult is obese = 0,357
Let's find the probability that an adult is either overweight or obese, that means both events are mutually exclusive. We are interested in the probability that just one event occurs, that probability is the sum of their individual probabilities
P(overweight ∪ obese) = P(overweight) + P(obese) = 0,331 + 0,357 = 0,688
