Answer:
Therefore you can wear your rings in =336 ways
Step-by-step explanation:
Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy
Given that you have 3 different rings.
We have total 10 figures.
But you don't wear ring on your thumbs.
We have 2 thumbs.
So you can wear rings on (10-2) = 8 figures.
The ways of wearing of first ring is = 8
The ways of wearing of second ring is = 7
The ways of wearing of third ring is = 6
Therefore you can wear your rings in =(8×7×6)
=336 ways
I think it’s 22 or 23...I’m so sorry if it’s wrong :/
The equation would be -5+(-12), so the answer would be -17 :)
<span>Let a_0 = 100, the first payment. Every subsequent payment is the prior payment, times 1.1. In order to represent that, let a_n be the term in question. The term before it is a_n-1. So a_n = 1.1 * a_n-1. This means that a_19 = 1.1*a_18, a_18 = 1.1*a_17, etc. To find the sum of your first 20 payments, this sum is equal to a_0+a_1+a_2+...+a_19. a_1 = 1.1*a_0, so a_2 = 1.1*(1.1*a_0) = (1.1)^2 * a_0, a_3 = 1.1*a_2 = (1.1)^3*a_3, and so on. So the sum can be reduced to S = a_0 * (1+ 1.1 + 1.1^2 + 1.1^3 + ... + 1.1^19) which is approximately $5727.50</span>
Answer:
yess queen
Step-by-step explanation:
why not
