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lesya [120]
3 years ago
15

SOMEONE PLEASE HELP I NEED HELP THANK YOU

Mathematics
2 answers:
GaryK [48]3 years ago
5 0
1) the graph is attached.
2) ∠A = ∠A; ∠B = ∠B; ∠C = ∠D; AC/BD = AD/BC = AB/AB
3)  The rise from A to D is 4.5; the run from D to B is 9; the slope is 4.5/9 = 1/2.
 The rise from C to B is 4.5; the run from A to C is 9; the slope is 4.5/9 = 1/2.

Lynna [10]3 years ago
4 0

Answer:

1) the graph is attached.

2) ∠A = ∠A; ∠B = ∠B; ∠C = ∠D; AC/BD = AD/BC = AB/AB

3)  The rise from A to D is 4.5; the run from D to B is 9; the slope is 4.5/9 = 1/2.

 The rise from C to B is 4.5; the run from A to C is 9; the slope is 4.5/9 = 1/2.

Step-by-step explanation:

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A store sells almonds for $7 per pound, cashews for $10 per pound, and walnuts for $12 per pound. A customer buys 12 pounds of m
kifflom [539]
First we need to write the equations for the given scenario. Using the equations, we can form a system of matrix for the situation.

Let the customer buys, x pounds of almonds, y pounds of cashews and z pounds of walnuts. Since he buys 12 pounds of mixed nuts, we can write:

x+y+z=12 

Total cost of these mixed nuts was $118. So we can write:

7x+10y+12z=118

Customer buys 2 more pounds of walnut than cashews. So, we can write:

z=y+2 \\  \\ 
-y+z=2

Using these equations, we can set up the system of matrix as shown below in the image.




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4 years ago
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What is the solution set to the inequality
creativ13 [48]

(4x - 3)(2x - 1) \geqslant 0 \\ \Leftrightarrow \begin{cases}4x - 3 \geqslant 0 \\ 2x - 1 \geqslant 0\end{cases}\: \vee \:\begin{cases}4x - 3 \leqslant 0 \\2x - 1 \leqslant 0 \end{cases} \\ \Leftrightarrow \begin{cases}x \geqslant  \frac{3}{4}  \\ x  \geqslant  \frac{1}{2} \end{cases}\: \vee \:\begin{cases}x\leqslant  \frac{3}{4}  \\x \leqslant  \frac{1}{2}  \end{cases} \\ \Leftrightarrow x \geqslant  \frac{3}{4} \: \vee \: x \leqslant  \frac{1}{2}  \\ \Rightarrow The\: third\: option

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3 years ago
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Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

AB = CD and AD = BC

The area of a rectangle:

A=(AB)(AD)

Substitute:

A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20

The perimeter of a rectangle:

P=2(AB+AD)

Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

4 0
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