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2 years ago

Beinggreat78 please answer

Mathematics

1 answer:

exis [7]2 years ago

3 0

$\boxed{\sf A.~530.66}\boxed$

________

$\sf Solve$

$\sf Given~diameter~is~26~centimeters$

$\sf Use~diameter-to-area~formula$

$\sf Formula:$ $\frac{1}{4} \pi d^2 = \frac{1}{4} * \pi * [diameter]^2$

________

$\sf Solve(Equation/Result)$

$\frac{1}{4} * \pi * d(26)^2 = 530.66~cm^2$

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Call the notebooks x, and the pencils y.
3x + 4y = $8.50 and 5x + 8y = $14.50 
Then just solve as simultaneous equations: 
3x + 4y = $8.50 
5x + 8y = $14.50 

5(3x + 4y = 8.5) 
3(5x + 8y = 14.5) 

15x + 20y = 42.5 
15x + 24y = 43.5 

Think: DASS (Different Add, Similar Subtract). 15x appears in both equations so subtract one equation from the other. Eassier to subtract (15x + 20y = 42.5) from (15x + 24y = 43.5) 

(15x + 24y = 43.5) - (15x + 20y = 42.5) = (4y = 1) which means y = 0.25. 

Then substitue into equation : 
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So x (notebooks) are 2.5 ($2.50) each and y (pencils) are 0.25 ($0.25) each.

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