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andriy [413]
2 years ago
10

I'm having trouble filling this chart out and need some help please.​

Mathematics
1 answer:
777dan777 [17]2 years ago
7 0

Answer:

Figure 1: complementary

figure 2: adjacent

figure 3: supplementary

figure5: supplementary

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LekaFEV [45]


= > x + \frac{1}{3} = 9



\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}



= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}




Hence,


Value \: \: \: of \: \: x \: \: is \:  \frac{26}{3} \: \: \: or \: \: \: 8. \bar{6}
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