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hjlf
3 years ago
15

Which points are the approximate locations of the foci of the ellipse? Round to the nearest tenth. (−2.2, 4) and (8.2, 4) (−0.8,

4) and (5.2, 4) (3, -1.2) and (3, 9.2) (3, 1.3) and (3, 6.7) PLEASE HURRY!!! IM TIMED!!!!!!!!!!!

Mathematics
2 answers:
sasho [114]3 years ago
8 0
To solve this problem you must apply the proccedure shown below:
 1. You have to find the distance from the center to the focus, as below:
 c=√(a^2-b^2)
 Where a is the major radius and b is the minor radius.
 2. Therefore, by the graph, you have:
 a=6
 a^2=36
 b=3
 b^2=9
 3. When you substitute the values, you obtain:
 c=5.2
 4. As you can see in the graph, the coordinates of the center is (3,4), then, the locations of the foci:
 3+c=8.2
 3-c=-2.2
 The answer is: (-2.2,4) and (8.2,4)
cestrela7 [59]3 years ago
6 0

Answer:

(−2.2, 4) and (8.2, 4)

Step-by-step explanation:

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Consider this exponential equation:
ioda

Step-by-step explanation:

F( <em>x</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>(</em><em>3</em><em>)</em><em> </em><em>^</em><em> </em><em>x</em>

<em>Y</em><em> </em><em>intercept</em><em> </em>

<em>Let</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>1</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em>

<em>X</em><em> </em><em>intercept</em><em> </em>

<em>let</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>o</em>

<em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em>x</em>

<em>No</em><em> </em><em>x</em><em> </em><em>intercept</em><em>/</em><em> </em><em>zero</em>

<em>therefore</em><em> </em>

<em>Vertical</em><em> </em><em>intercept</em><em> </em><em>(</em><em>0</em><em>;</em><em> </em><em>5</em><em>)</em>

<em>Domain</em><em> </em><em>XER</em>

<em>▪︎</em><em>this</em><em> </em><em>refer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>X</em>

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The following question has two parts. First, answer part A. Then, answer part B.
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Answer:

When you're talking factors, you're talking about some sort of integer; that's because “factors” depends on the concept of divisibility, which are virtually exclusive to integers. When you're talking “greater than”, you're excluding complex numbers (where the concept of ordering doesn't exist) and you're probably assuming positive integers. If you are, then no; no positive integer has factors that are larger than it.

If you go beyond positive numbers, that changes. 0 is an integer, and has every integer, except itself, as factors; since its positive factors are greater than zero, there are factors of zero that are greater than zero. If you extend to include negative numbers, you always have both positive and negative factors; and since all positive integers are greater than all negative integers, all negative integers have factors that are greater than them.

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Step-by-step explanation:

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