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hjlf
3 years ago
15

Which points are the approximate locations of the foci of the ellipse? Round to the nearest tenth. (−2.2, 4) and (8.2, 4) (−0.8,

4) and (5.2, 4) (3, -1.2) and (3, 9.2) (3, 1.3) and (3, 6.7) PLEASE HURRY!!! IM TIMED!!!!!!!!!!!

Mathematics
2 answers:
sasho [114]3 years ago
8 0
To solve this problem you must apply the proccedure shown below:
 1. You have to find the distance from the center to the focus, as below:
 c=√(a^2-b^2)
 Where a is the major radius and b is the minor radius.
 2. Therefore, by the graph, you have:
 a=6
 a^2=36
 b=3
 b^2=9
 3. When you substitute the values, you obtain:
 c=5.2
 4. As you can see in the graph, the coordinates of the center is (3,4), then, the locations of the foci:
 3+c=8.2
 3-c=-2.2
 The answer is: (-2.2,4) and (8.2,4)
cestrela7 [59]3 years ago
6 0

Answer:

(−2.2, 4) and (8.2, 4)

Step-by-step explanation:

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3 years ago
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After sitting in a refrigerator for a while, a turkey at a temperature of 34 degrees F is placed on the counter and slowly warms
Anton [14]

Answer:

  • k = 0.006
  • T = 48 °F

Step-by-step explanation:

The initial temperature difference of 72 -34 = 38 °F is reduced to a difference of 72 -41 = 31 °F after 35 minutes. The exponential term in the temperature expression could have the factor ...

  (31/38)^(t/35) = e^(-kt)

Taking the natural log, we find ...

  (t/35)ln(31/38) = -kt

  k = ln(38/31)/35 ≈ 0.00581711

To the nearest thousandth, this is ...

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Using this in the equation for temperature, we have ...

  T = 72 -38e^(-0.006t)

Filling in the desired value for t (80), we find the turkey temperature after 80 minutes to be about

  T = 72 -38e^(-.006×80) = 72 -38e^-.48 ≈ 48.49

  T ≈ 48 °F

The value of k is about 0.006, and the turkey temperature is about 48 °F.

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3 years ago
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This phrase is True.

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