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Vilka [71]
3 years ago
11

If KLMN is a square, then ___________________.

Mathematics
1 answer:
True [87]3 years ago
4 0

-Hello There-

A square is always a rhombus because it satisfies all the properties of rhombus but every rhombus cannot a square.

Therefore, If KLMN is a square, then it must be a rhombus.

Have A Fantastic Day

Be Safe,

TheBlueFox

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Write an equation of a line that has a slope of -1/2 in each form
konstantin123 [22]

Answer:

y=-1/2x+17

Step-by-step explanation:

y=-1/2x+17

4 0
3 years ago
HELLO AGAIN HERE'S ANTOHER QUESTION
puteri [66]
I believe it’s B but i’m not too sure.
4 0
2 years ago
Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

8 0
3 years ago
The temperature was -5 ℉ in Denver and then fell 8 ℉ by the morning.<br> Answer now please
allochka39001 [22]

Answer:

it was -5 and then it fell 8 degrees

-5 -8 = -13 degrees F

Step-by-step explanation:

8 0
3 years ago
Determine the sum of the parts 1 3/8 +2/3=
Mumz [18]

2 1/24

Rewriting our equation with parts separated

2/3+1+3/8

Solving the fraction parts

2/3+3/8=?

Find the LCD of 2/3 and 3/8 and rewrite to solve with the equivalent fractions.

LCD = 24

16/24+9/24=25/24

Simplifying the fraction part, 25/24,

25/24=1 1/24

Combining the whole and fraction parts

1+1+1/24=2 1/24

5 0
3 years ago
Read 2 more answers
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