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tankabanditka [31]
3 years ago
12

The table shows the total number of student applications to universities in a particular state over a period of 12 semesters. St

ates base their decisions on data like this. Suppose they decide that if fewer than 200,000 students apply during 6 or more semesters, the state will make a special effort to promote university education. Using this data, what is the population proportion of semesters for which the number of student applications is less than 200,000?
Mathematics
1 answer:
alexira [117]3 years ago
5 0
<span>A) there is insufficient data to answer this question 
</span><span>The answer is A because there REALLY is insufficient data to answer this question</span>
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what is the slope and equation of a line that is perpendicular to the y-axis passing through (-5,-3)?​
Illusion [34]

Answer:

Slope is m=0

y=-3

Step-by-step explanation:

The slope of any line that is perpendicular to the y-axis is zero.

The reason is that any line that is perpendicular to the y-axis is also parallel to the x-axis and the slope of the x-axis is zero.

The equation of any line perpendicular to the y-axis is and passes through (a,b) is y=b.

The given point is (-5,-3) hence the required equation is

y=-3

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2 years ago
PLEASE EXPLAIN Find the area and perimeter of the rectangle whose sides are lengths 2x + 3 and 4x
SIZIF [17.4K]

Area = 4x(2x + 3) = 8x2 + 12x

Perimeter = 2(2x + 3 + 4x) = 12x + 6

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What is the slope of the line that passes through the points (2, 1)(2,1) and (17, -17) ?(17,−17)? Write your answer in simplest
Yuliya22 [10]

Answer:

1 + +17 18

______ = ___ = m

2 + -17 -15

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2 years ago
What set of reflections would carry parallelogram ABCD onto itself?
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A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s
yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2}  = \frac{1 \pm 9 }{-0.4}

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0
2 years ago
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