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-Dominant- [34]
2 years ago
6

B) x⁴ + x² + 1 solve it​

Mathematics
2 answers:
LekaFEV [45]2 years ago
7 0

Answer: x⁶︎+1 or 2⁶︎

Step-by-step explanation: you add the exponents and because x technically has a 1 in front of it, you add 1+1 and end up with 2⁶︎

jasenka [17]2 years ago
3 0

Answer:

{x}^{4}  +  {x}^{2}  + 1 \\   {( {x}^{2} })^{2}  +  {x}^{2}  + 1 \\ let \:  {x}^{2}  \: be \: m \\ if \: f(m) = 0 \\  {m}^{2}  + m + 1 = 0 \\ factor \: of \: equation \:  = m +  \frac{1}{2}  \\ m =  -  \frac{1}{2}  \\ hence \:  {x}^{2}  =  \frac{1}{2}  \\ x =  \sqrt{ \frac{1}{2} }  \\

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What is the domain of the function y = 2 StartRoot x minus 5 EndRoot?
Juli2301 [7.4K]

Answer:

The domain of the function should be:

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Step-by-step explanation:

Given the expression

2\sqrt{x-5}

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x ≥ 5

In other words, the domain of the function should be:

'x greater than or equal to negative -5'.

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x ≥ 5

\mathrm{Domain\:of\:}\:2\sqrt{x-5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:5\:\\ \:\mathrm{Interval\:Notation:}&\:[5,\:\infty \:)\end{bmatrix}

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