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-Dominant- [34]
2 years ago
6

B) x⁴ + x² + 1 solve it​

Mathematics
2 answers:
LekaFEV [45]2 years ago
7 0

Answer: x⁶︎+1 or 2⁶︎

Step-by-step explanation: you add the exponents and because x technically has a 1 in front of it, you add 1+1 and end up with 2⁶︎

jasenka [17]2 years ago
3 0

Answer:

{x}^{4}  +  {x}^{2}  + 1 \\   {( {x}^{2} })^{2}  +  {x}^{2}  + 1 \\ let \:  {x}^{2}  \: be \: m \\ if \: f(m) = 0 \\  {m}^{2}  + m + 1 = 0 \\ factor \: of \: equation \:  = m +  \frac{1}{2}  \\ m =  -  \frac{1}{2}  \\ hence \:  {x}^{2}  =  \frac{1}{2}  \\ x =  \sqrt{ \frac{1}{2} }  \\

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Which linear equation has no solution?
olga_2 [115]

Answer:

Option A

Step-by-step explanation:

Given:

  • a. 3x-5= 3x + 5
  • b. 3x-5= 3x - 5
  • c. 3x - 5 = 2x+5
  • d. 3x-5 = 2x + 10

To find:

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Solution:

a)  3x-5= 3x + 5

Add 5 to both sides

3x-5= 3x + 5

3x - 5 + 5 = 3x + 5 + 5

Simplify

(Add the numbers)

3x - 5 + 5 = 3x + 5 + 5

3x = 3x + 5 + 5

(Add the numbers)

3x  = 3x + 5 + 5

3x = 3x + 10

Subtract 3x from both sides

3x = 3x + 10

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Simplify

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(Combine like terms)

0 = 3x + 10 - 3

0 = 10

The input is a contradiction: it has no solutions

b)  3x-5= 3x - 5

Since both sides equal, there are infinitely many solutions.

c)  3x - 5 = 2x+5

Add 5 to both sides

3x = 2x + 5 + 5

Simplify  2x + 5 + 5 to 2x + 10

3x = 2x + 10

Subtract 2x from both sides

3x - 2x = 10

Simplify 3x - 2x to x.

x = 10

d) 3x-5 = 2x + 10

Add 5 to both sides

3x = 2x + 10 + 5

Simplify 2x + 10 + 5 to 2x + 15

3x = 2x + 15

Subtract 2x from both sides

3x - 2x = 15

Simplify 3x -2x to x.

x = 15

--------------------------------------------

Answer:

As you can see all c and d both have solutions, eliminating them as options. Option B has infinite solutions leaving Option A which has no solutions.

Therefore, <u><em>Option A</em></u> is the linear equation that has no solution.

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