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-Dominant- [34]
3 years ago
6

B) x⁴ + x² + 1 solve it​

Mathematics
2 answers:
LekaFEV [45]3 years ago
7 0

Answer: x⁶︎+1 or 2⁶︎

Step-by-step explanation: you add the exponents and because x technically has a 1 in front of it, you add 1+1 and end up with 2⁶︎

jasenka [17]3 years ago
3 0

Answer:

{x}^{4}  +  {x}^{2}  + 1 \\   {( {x}^{2} })^{2}  +  {x}^{2}  + 1 \\ let \:  {x}^{2}  \: be \: m \\ if \: f(m) = 0 \\  {m}^{2}  + m + 1 = 0 \\ factor \: of \: equation \:  = m +  \frac{1}{2}  \\ m =  -  \frac{1}{2}  \\ hence \:  {x}^{2}  =  \frac{1}{2}  \\ x =  \sqrt{ \frac{1}{2} }  \\

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Multiply<br><br> (2t^2-t-8)(2t^2+2t-1)
algol13

(2t^2−t−8)(2t^2+2t−1)

= (2t^2+−t+−8)(2t^2+2t+−1)

= (2t^2)(2t^2) + (2t^2)(2t) + (2t^2)(−1) + (−t)(2t^2) + (−t)(2t) + (−t)(−1) + (−8)(2t^2) + (−8)(2t) + (−8)(−1)

=4t^4+4t^3−2t^2−2t^3−2t^2+t−16t^2−16t+8

=4t^4+2t^3−20t^2−15t+8

Sorry if I made it too complicated

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4 years ago
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amid [387]
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3 years ago
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