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KATRIN_1 [288]
3 years ago
9

Factor completely W^3-64

Mathematics
1 answer:
Ivenika [448]3 years ago
5 0
<span>Trinomial can not be factored 

</span>
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Wat is 2 and 3 7ths divided by 7
Alchen [17]
 3................................
3 0
3 years ago
in a bag the coins of 50 Paisa 25 paisa and 10 paisa are in the ratio of 2:3: 5 and its total value is rupees 90​
IgorLugansk [536]

Answer:

It is given 50 paise, 25 paise and 10 paise are in the ratio 2:3:5. =4:3:2.

Step-by-step explanation:

Hope this helps

5 0
3 years ago
Which number is rational , square root 2 , pi , square root 10 or square 16
melamori03 [73]

The square root of 16 is rational.

8 0
3 years ago
Read 2 more answers
Tiffany sees this given dilation and claims that the scale factor is 2
Alenkinab [10]

Answer:

The scale factor is not 2

Step-by-step explanation:

Given

See attachment for the dilated triangles

Triangle ABC is dilated through center point O to form triangle A'B'C'.

From the attachment, we have:

OC = 2 i.e. the distance from the center point to C

and

OC' = 6 i.e. the distance from the center point to C'

The length of OC' is calculated using:

OC' = OC + CC'

OC' = 2 + 4

OC' = 6

The scale factor (k) is then calculated by dividing OC' by OC

k = \frac{OC'}{OC}

k = \frac{6}{2}

k = 3

Hence, Tiffany's claim is incorrect.

5 0
3 years ago
When purchasing bulk orders of​ batteries, a toy manufacturer uses this acceptance sampling​ plan: Randomly select and test 56 b
nydimaria [60]

Answer:

98.1% chance of being accepted

Step-by-step explanation:

Given:

sample size,n=56

acceptance condition= at most 2 batteries do not meet specifications

shipment size=7000

battery percentage in shipment that do not meet specification= 1%

Applying binomial distribution

<h3>P(x)=∑ᵇₐ=₀ (n!/a!(n-a)!)p^a (1-p)^(n-a)</h3>

In this formula, a is the acceptable number of defectives;

 n is the sample size; 

p is the fraction of defectives in the population.  

Now putting the value

a= 2

n=56

p=0.01

\frac{56!}{0!\left(56-0\right)!}\left(0.01\right)^0\:\left(1-0.01\right)^{\left(56-0\right)} + \frac{56!}{1!\left(56-1\right)!}\left(0.01\right)^1\:\left(1-0.01\right)^{\left(56-1\right)} +\:\frac{56!}{2!\left(56-2\right)!}\left(0.01\right)^2\:\left(1-0.01\right)^{\left(56-2\right)}

=0.56960+0.32219+0.08949

After summation, we get 0.981 i.e. a 98.1% chance of being accepted.  As this is such a high chance, we can expect many of the shipments like this to be accepted!

7 0
3 years ago
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