All categories

3 years ago

5. How many standard deviations from the mean is the weight of 190 people?

Mathematics

1 answer:

Gemiola [76]3 years ago

3 0

Answer:

i think that the correct C

Step-by-step explanation:

You might be interested in

If a car is moving with an average velocity of 25 m/s how long will it take the car to travel 1500m

Bond [772]

Answer:

Step-by-step explanation:

60m/s

8 0

3 years ago

Read 2 more answers

Mia's cat weighs 13 pounds, 7 ounces. About what is that weight in kilograms? (Hint: 1 kilogram = 1,000 grams.

sattari [20]

Given:
13 pounds and 7 ounces

convert to kilograms:

1 kilogram = 2.20462 pounds
1 kilogram = 35.274 ounces

13 pounds * 1 kg/2.20462 pounds = 13 kg/2.20462 = 5.8967 kg
7 ounces * 1kg/35.274 ounces = 7 kg/35.274 = 0.1984

5.8967 kg + 0.1984 = 6.0951 kg. rounded up to 6.10 kgs.

5 0

4 years ago

3. A theater has 60 seats in the first row, 68 seats in the second row. 76 seats in the

Airida [17]

Answer:

Step-by-step explanation:

arithmetic sequence: 60,68,76,......

a = 60

d = 68 - 60 = 8

an = a + (n-1)*d

a20 = 60 + 19 * 8

= 60 + 152

= 112

There are 112 seats in the 20th row

4 0

3 years ago

Alex wrote the expanded form for the number 165.038 as “100 + 60 + 5 + 30 + 8.” Was he correct? If not, give the correct expande

ivann1987 [24]

No, Alex is wrong. The correct expanded form would be 100+60+5+.03+.008

8 0

3 years ago

Read 2 more answers

58.(A) (5pts)A certain type of bacteria, given favorable growth medium, quadruples in population every 6 hours. Given that there

Jet001 [13]

Answer:

157286400 bacteria

Step-by-step explanation:

We are given the following in the question:

The bacteria increases 4 times every 6 hours.

Initially there are 150 bacteria.

Thus, we can write the function for number of bacteria after x hours,

$f(x) = 150(4)^{\frac{x}{6}}$

We have to find the number of bacteria in 2.5 days.

1 day = 24 hours

Thus,

$2.5\text{ days} = 24\times 2.5 = 60\text{ hours}$

Putting x = 60 in the above equation, we get,

$f(60) = 150(4)^{\frac{60}{6}} = 150(4)^{10} = 157286400$

Thus, there will be 157286400 bacteria in two and a half days.

5 0

4 years ago