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2 years ago

5

3 4/9x5/9 will be lesser or greater than 3 4/9

1 answer:

Dmitry_Shevchenko [17]2 years ago

3 0

It equals 1 74/81 which is less than 3 4/9

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Using identities, find a)(2 + 3) 2 b) (x+2y) (x-2y)

shutvik [7]

Pop ok you see so the answer here would be frantically elastic

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2 years ago

Which expression is equivalent to – 12 + (-4/5) + 31 and includes the correct justification for the equivalence?

anyanavicka [17]

Answer:

b

Step-by-step explanation:

8 0

2 years ago

Please anyone help i really need help it’s due please!!

Diano4ka-milaya [45]

Answer: w = 41

QU = 2(RT)

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6 0

2 years ago

Generate the nest three terms of each arithmetic sequence shown below.

o-na [289]

Answer:

A)2,6,10

B)2,-6,-18

C)-1,-3,-5

Step-by-step explanation:

<u>A)a1=-2 and d=4</u>

We know that the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{2}=a_{1}+(2-1)d$

$a_{2}=a_{1}+(1)d$

Substituting the given value we get

$a_{2}= -2+(1)4$

$a_{2}= -2+4$

$a_{2}= 2$

------------------------------------------

Similarly

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the given value we get

$a_{3}= -2+(2)4$

$a_{3}= -2+8$

$a_{3}= 6$

-------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the given value we get

$a_{4}= -2+(3)4$

$a_{4}= -2+16$

$a_{4}= 10$

-------------------------------------------------------------------------------------------

<u>B</u><u> $a_n=a_{(n-1)}-8$ with $a_1=10$ </u>

$a_2=a_{(2-1)}-8$

$a_2=a_{1}-8$

Substituting the given value

$a_2= 10-8$

$a_2=2$

---------------------------------------------------------------------

$a_3=a_{(3-1)}-8$

$a_3=a_{2}-8$

Substituting the value

$a_3=2-8$

$a_3= -6$

---------------------------------------------------------------------

$a_4=a_{(4-1)}-8$

$a_4=a_{3}-8$

Substituting the value

$a_4= -6-8$

$a_4= -14$

-------------------------------------------------------------------------------------------

<u>C) $a_1=3, a_2=1$ </u>

Here the difference is -2

the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the value we get

$a_{3}= 3+(2)-2$

$a_{3}= 3-4$

$a_{3}= -1$

------------------------------------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the value we get

$a_{4}= 3+(3)-2$

$a_{4}= 3-6$

$a_{4}= -3$

----------------------------------------------------------------------------------

$a_{5}=a_{1}+(5-1)d$

$a_{5}=a_{1}+(4)d$

Substituting the value we get

$a_{5}= 3+(4)-2$

$a_{5}= 3-8$

$a_{5}= -5$

4 0

2 years ago

Hey can you please help me posted picture of question

vredina [299]

The correct Option is (A) 35x^3 - 16x^2 + 44x - 48

Explanation: The product of the polynomials (5x^2 + 2x +8)(7x-6) is:

(5x^2)(7x-6) + 2x(7x-6) +8(7x-6)

35x^3 -30x^2 + 14x^2 - 12x + 56x - 48
35x^3 - 16x^2 + 44x - 48 (Option A)

6 0

2 years ago