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amm1812
3 years ago
5

3 4/9x5/9 will be lesser or greater than 3 4/9

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0
It equals 1 74/81 which is less than 3 4/9
You might be interested in
2. Write the mixed number -5(4/9) as a fraction in three different ways. Thenwrite the mixed number as a decimal.
emmasim [6.3K]

<em>Fraction #1</em>

-5\frac{4}{9}

<em>Fraction #2</em>

-\frac{49}{9}

<em>Fraction #3</em>

-4\frac{13}{9}

<em>Fraction #4</em>

-3\frac{22}{9}

<em>Decimal:</em>

-5\frac{4}{9}\approx5.4444

Answer:

-5\frac{4}{9}

<em />

-\frac{49}{9}

<em />

-4\frac{13}{9}

<em>Decimal: 5.4444</em>

3 0
1 year ago
Guys can u help me asap ?? i need explaination aloong the answer
Alisiya [41]

Answer:

5225 x 5/100 = 261.25

5225 - 261.25 = 4963.75

Step-by-step explanation:

We know that % means a 100 so if they say they allowed a 5% discount then that would be 5/100.

You will take the fraction and multiple it with the original price. It will then give you the discount price, you will then need to subtract the discounted amount from the original sale price which is 5225. Then you will get your final answer.

;-)

5 0
3 years ago
Choose the correct written expression for: 25 – (3 x 4).
netineya [11]

Answer:

13

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the area of this figure? ​
Delvig [45]

Answer:

33

Step-by-step explanation:

5 0
2 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
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