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ivann1987 [24]
3 years ago
15

Please  help ill mark brainliest!!

Mathematics
1 answer:
kompoz [17]3 years ago
7 0
If sides are congruent then the angles ACROSS from them are also congruent.
Since WV and VU are congruent, angle U is congruent to angle W.
Set up an equation and solve.
See attachment.
x = 8
Angle w = 63

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A bus travels with a constant speed of 48 miles per hour. How long will it take to travel 60 miles? Write your answer as a decim
mrs_skeptik [129]
1 hour and 15 minutes
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2 years ago
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Find the square root of 25/49
Nuetrik [128]

Answer: 5/7

Step-by-step explanation:

Just take the square root of the top and the bottom. Square root of 25=5 and the square root of 49=7, so the square root of 25/49=5/7

5 0
3 years ago
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50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

(DE)^2+(DF)^2=(EF)^2

Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

6 0
3 years ago
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Write the equation of the line in fully simplified slope-intercept form.
coldgirl [10]
Y= -1/2x - 4

hope this helps! :)
7 0
3 years ago
F(x)=-2x^2-2x+10 f(x)=−2x 2 −2x+10 \text{Find }f(2) Find f(2)
romanna [79]

Given that:

f(x) = -2x²-2x+10

f(2) = -2(2)²-2(2)+10

= -2(2*2) - 4 + 10

= -2(4) - 4 + 10

= -8 - 4 + 10

= -12 + 10

= -2 Ans.

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Given f(x) = 1/2x - 5, find f^-1(x) a. f^-1 (x) = -2x+10 b. f^-1(x) = 2x+5 c. f^-1(x) = 2x-10 d. f^-1(x) = 2x+10...

brainly.com/question/11148895?referrer

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