Answer: see last picture
Step-by-step explanation:
We see that the y-intercept is 10 and the slope is -3
so when x = 0, y = 10
Graph this first point (picture 1)
Since the slope is -3, every time you go one unit to the left, you go down 3 units, so graph this second point (picture 2)
Continue this until you have no more room on the graph (picture 3)
now draw a line through the dots (picture 4)
<span>14% per year
</span>14% /12 = 1.2% is <span> the monthly growth rate</span>
Answer:
(a) 283 days
(b) 248 days
Step-by-step explanation:
The complete question is:
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?
Solution:
The random variable <em>X</em> can be defined as the pregnancy length in days.
Then, from the provided information
.
(a)
The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:
P (X > x) = 0.11
⇒ P (Z > z) = 0.11
⇒ <em>z</em> = 1.23
Compute the value of <em>x</em> as follows:

Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.
(b)
The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:
P (X < x) = 0.05
⇒ P (Z < z) = 0.05
⇒ <em>z</em> = -1.645
Compute the value of <em>x</em> as follows:

Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.
Answer:
Function: 
Not Function:
and 
Step-by-step explanation:
Given



Required
Determine if
is a function of 
Solving x+y=9

Make y the subject of formula

<em>Hence; y is a function of x</em>
Solving 

Subtract x² from both sides

Square root of both sides

This implies that
or 
<em>Because </em>
<em> can be any of those two expressions, it is not a function.</em>
Solving 

Reorder

Take square roots

This implies that
or 
<em>Because </em>
<em> can be any of those two expressions, it is not a function.</em>
Answer:
<h2> 3hours 55 minute</h2>
Step-by-step explanation:
Step one:
Given data
distance= 160miles
velocity = 3/4 miles per minutes
Step two:
Required:
time
we know that velocity is
v=distance/time
times= distance/velocity
time=160/3/4
time= 160*4/3
time=640/3
time=213.33333minuts
Time= 3hours 55 minute